A specimen of steel has a gauge length of 50 mm and a cross-section which measures20 mm x 5 mm. It gave the following results when subjected to a tensile test.ExtensionLoad (kN)(mm)0.330.0252.970.0605.600.0918.300.13010.950.18413.570.25814.900.39315.530.60015.931.06716.607.769From these results, plot stress-strain curve and determine:24. 0.2% Proof stress for the material [2 Marks]25. The percentage elongation at failure [2 Marks]

To Calculate StressThe load values are given in kN, which we convert to Newtons (1 kN = 1000 N) to…

Answered: A specimen of steel has a gauge length…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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A tension test was performed on a specimen having an original diameter of 13.7 mm and a gauge length of 50 mm. The data are listed in the table. Load (kN) Elongation (mm) 0 11.1 31.9 37.8 40.9 43.6 53.4 62.3 64.5 62.3 58.8 0 0.0175 0.0600 0.1020 0.1650 0.2490 1.0160 3.0480 6.3500 8.8900 11.9380 Plot the stress-strain diagram. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Redraw the linear-elastic region, using the same stress scale but a strain scale of 20 mm = 0.001 mm/mm. From the diagram, determine approximately the modulus of elasticity. Express your answer to three significant figures and include the appropriate units. E = Submit Part B συ = Submit Part C ☐☐ μÅ of = Value Determine the ultimate stress. Express your answer to three significant figures and include the appropriate units. Request Answer μĂ Value Request Answer Units μĂ - Value Units Determine the fracture stress. Express your answer to three significant figures and include the appropriate units. ? Units ? ?
A tension test was performed on a specimen having an original diameter of 13.0 mm and a gauge length of 50 mm. Load (kN) Elongation (mm) 0 11.1 31.9 37.8 40.9 43.6 53.4 62.3 64.5 62.3 58.8 0 0.0175 0.0600 0.1020 0.1650 0.2490 1.0160 3.0480 6.3500 8.8900 11.9380 Using the data listed in the table, plot the stress-strain diagram. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Part A From the diagram, determine approximately the modulus of toughness. Express your answer to three significant figures and include the appropriate units. U = Submit O μA Value Request Answer Units < Return to Assignment Provide Feedback ?
A tension test was performed on a specimen having an original diameter of 11.5 mm and a gauge length of 50 mm. The data are listed in the table. Load (kN) Elongation (mm) 0 11.1 31.9 37.8 40.9 43.6 53.4 62.3 64.5 62.3 58.8 0 0.0175 0.0600 0.1020 0.1650 0.2490 1.0160 3.0480 6.3500 8.8900 11.9380 Plot the stress-strain diagram. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Redraw the linear-elastic region, using the same stress scale but a strain scale of 20 mm = 0.001 mm/mm. From the diagram, determine approximately the modulus of elasticity. Express your answer to three significant figures and include the appropriate units. E 215 Submit Previous Answers Request Answer Part B μÀ X Incorrect; Try Again; 2 attempts remaining Tu = 530 Determine the ultimate stress. Express your answer to three significant figures and include the appropriate units. GPa μÅ Part C Submit Previous Answers Request Answer MPa | μA ? X Incorrect; Try Again; 2 attempts remaining of=479.15 Determine the…
I want answers to all four questions if possible. Thanks for help :) Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the fracture strength (in MPa) of the material. - Calculate the percent elongation of the specimen at fracture point. - Determine the modulus of resilience (in N.mm/mm3) of the material. (Use at least five decimal units) - Determine the toughness index number (in N.mm/mm3) of the material.
The following data were recorded during the tensile test of a test specimen with a diameter of 12.8 mm. The gage length is 50.8 mm. The given data are as follow; Given: Test specimen material: Aluminum Diameter of test specimen: Do = 12.8 mm Length of test specimen: Lo = 50.8 mm Force and Elongation data for test specimen Assumptions: 1. The given data is accurate and the material is isotropic 2. The direction of applied force is parallel to the length of the cylinder Requirement: To interpret and plot the stress Vs Strain curve for a given specimen DATA: LENGTH, mm STRESS, MPa LOAD, N 0 50.8 7 330 50.851 15 100 50.902 23 100 50.952 30 400 51.003 34 400 51.054 38 400 51.308 41 300 51.816 44 800 52.832 46 200 53.848 47 300 54.864 47 500 55.88 36 100 56.896 44 800 57.658 42 600 58.42 36 400 59.182 STRAIN
QUESTION The following data were obtained during a tension test of a low carbon steel specimen having a gauge length of 100 mm. At the point where the stress strain curve deviated from linearity, the load was 35KN, the gauge length was 102.5 mm and the diameter of the specimen was 1.6 mm. Before necking began, loads of 45 KN and 55 KN produced gauge lengths of 103.4 mm and 107.7 mm respectively. Calculate (a) The Modulus of elasticity (b) The Strainhardening exponent
Question Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the yield strength (in MPa) of the material. - Calculate the percent elongation of the specimen at yield point. (Use at least five decimal units) - Calculate the stiffness (in MPa) of the specimen material. - Calculate the ultimate strength (in MPa) of the material. - Calculate the percent elongation of the specimen at point of ultimate strength.
1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 20.31 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 0 6 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3
10. The following results were obtained in a tensile test on a mild steel specimen of original diameter 20 mm and gauge length 40 mm. Load at limit of proportionality 80 kN Extension at 80 kN load 0.048 mm Load at yield point 85 kN Maximum load 150 kN When the two parts were fitted together after being broken, the length between gauge length was found to be 55.6 mm and the diameter at the neck was 15.8 mm. Calculate Young's modulus, yield stress, ultimate tensile stress, percentage elongation and percentage [Ans. 213 kN/mm2; 270 N/mm²; 478 N/mm²; 39%; 38%] reduction in area.
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. Question 1 ;Determine the elastic energy absorption capacity (in N.mm) of that specimen. Question 2; Determine the plastic energy absorption capacity (in N.mm) of that specimen.
The percentage of reduction in area of The final area would be: magnesium tensile specimen was 25%, the gauge length was (56mm) and the initial diameter was (20mm). 235.619 Choose the correct answers for the following 320.159 sentences: 285.619 The finial length would be 314.159 70.67 80.67 74.67 % Elongation of specimen would 76.67 be 33.34 The final diameter would be 36.911 19.32 18.32 44.053 15.32 26.196 17.32
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Determine the true stress (in MPa) at yield point. - Determine the true stress (in MPa) at point of ultimate strength. - Determine the true stress (in MPa) at fracture point. - Determine the true strain (in mm/mm) at yield point. (Use at least five decimal units) - Determine the true strain (in mm/mm) at point of ultimate strength. (Use at least five decimal units) - Determine the true strain (in mm/mm) at fracture point. (Use at least five decimal units)

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