Kepler’s third law can be stated mathematically as: velocity = distance/time (years)2 = (A.U.)3 S = vot + ½ (a) t2 vm = ½ (vo + vf) F = GM1M2/d2
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- Kepler’s third law can be stated mathematically as:
- velocity = distance/time
- (years)2 = (A.U.)3
- S = vot + ½ (a) t2
- vm = ½ (vo + vf)
- F = GM1M2/d2
Step by step
Solved in 2 steps with 3 images
- You have measured the following data for enzyme X. Substrate Vo concentration (micromolar (mM) Isec) 0.05 10 0.1 60 0.5 175 1 250 350 490 10 492 20 494 50 499 100 498 200 498Based on the speculations of Nicole Oresme, and on the equation relating spatial distance, time, initial velocity, and constant acceleration developed by the Mertonian Calculators, how far would you expect a falling object to travel in 4 seconds (falling from a spaceship towards the Earth, in the vacuum of space), starting at 0 feet/second, with constant acceleration (32 feet/sec2), and neglecting possible air friction? 64 feet 144 feet 256 feet 400 feet 576 feetUsing the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 80 km/hour (final speed) over a 5-minute period of time. average velocity over 5 minutes = 16 kilometers/hour average velocity over 5 minutes = 20 kilometers/hour average velocity over 5 minutes = 24 kilometers/hour average velocity over 5 minutes = 32 kilometers/hour average velocity over 5 minutes = 40 kilometers/hour
- Which of the following components of Km is largest in magnitude? k2 O k-1 O k1 O k-2why is the maximum velocity in the michaeli's equation not touching the rectangular hyperbolic curve1-Using the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 90 km/hour (final speed) over a 5 minute period of time. A. average velocity over 5 minutes = 45 kilometers/hour average velocity over 5 minutes = 30 kilometers/hour average velocity over 5 minutes = 18 kilometers/hour average velocity over 5 minutes = 15 kilometers/hour average velocity over 5 minutes = 12 kilometers/hour
- Write C if only statement A is correct, H if only statement B is correct, E if both statements are correct, M if both statements are incorrect. (A) For the Lineweaver-Burk plot, the slope of the line reflects the ratio between the maximum velocity and the Michaelis constant. (B) Meanwhile, the y-intercept is the maximum velocity.Graphically derive the value of KM from a Michaelis-Menten PlotFrom the equation of a lineweaver-burke plot, calculate Km and Vmax. Show your work and include units. The equation is y=393.4x +8.4337
- For the following reaction 3 experiments have been run and the data collected is in the following table @ 35 degrees Celsius 2 NO2F(g) ---> 2 NO2(g) + F2(g) Experiment [NO2F], M Rates, M/s 1 0.263 0.168 2 0.349 0.223 3 0.421 0.269 a) How long will it take for a 65% NO2F solution to become a 31% NO2F solution @35 degrees Celsius?(Hint: Use mass ratios and assume ~1g/ml for density of solutions to get you started) b) It has been determined that at 75 degrees Celsius the rate constant is 1.046 s-1. Calculate the activation energy for the decomposition of NO2F. [Hint: ]ln?1?2=?a?(1?2―1?1) c) What is the half-life of a 35% solution of NO2F @ 35 degrees Celsius?Vo [S] S1 S2 0.0001 33 17 0.0002 50 29 0.0005 71 50 0.001 83 67 0.002 91 80 0.005 96 91 0.01 98 95 0.02 99 98 0.05 100 100 5.0 100 100 Which of the following is a correct conclusion from this data? A) the Km for both Si and S2 is 100 B) the Km for both Si and S2 is 50 C) the Km for both S1 and S2 is 5.0 D) the Km for Sı is 0.0002 and for S2 is 0.0005 E) the Km for Sı is 50 and for S2 is 29 Which of the following is a correct conclusion from this data? A) Sı is a better substrate because it has a higher Vmax B) S2 is a better substrate because it has a higher Vmax Si is a better substrate because it has a lower Km D) Si is a better substrate because it has a higher Km E) None of the above In plots of 1/V vs. 1/[S], the Y-intercept (i.e. the value of Y when X = 0) is S2. for both Sı and A) 5 B) 1/5 C) 100 D) 1/100 E) None of theseAccording to Jean Buridan’s equation, the momentum or “impetus” of an 8 kilogram mass moving at 48 meters per second would be: 192 kilogram-meters per second 384 kilogram-meters per second 576 kilogram-meters per second 768 kilogram-meters per second 960 kilogram-meters per second