In humans, brown eyes (B) are dominant over blue (b)*. A brown-eyed man marries a blue-eyed woman and they have three children, two of whom are brown-eyed and one of whom is blue-eyed. Draw the Punnett square that illustrates this marriage. What is the man's genotype? What are the genotypes of the children?
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- Assuming brown eyes (B) are dominant over blue eyes (b), determine the genotypes of all the following individuals. The blue-eyed son of two brown-eyed parents marries a brown-eyed woman whose mother was brown eyed and whose father was blue eyed. Their child is blue eyed.in humans brown eyes (B) are dominant over blue (b).A brown eye man marries a blue-eyed woman and they have three children , two of whom are brown eyed and one of whom is blue eyed.Draw the punnett square that illustrate this marrage.what is the man's genotype ? what are the genotype of the children?In humans, brown eyes (B) are dominant over blue. A brown eyed man marries a blue-eyed (b) woman and they have three children two of whom are brown-eyed and one of whom is blue-eyed. if the male has brown eyes but has a blue-eyed child, what must his genotype be?
- In humans, brown eyes (B) are dominant over blue. A brown eyed man marries a blue-eyed (b) woman and they have three children two of whom are brown-eyed and one of whom is blue-eyed. what are the possible genotypes of the children?In humans, Widow’s peak (W) is dominant over a continuous hairline (w), and short fingers (F) are dominant over long fingers (f). Two individuals with widow’s peaks and short fingers have a child with a continuous hairline and long fingers. Determine the genotype of the parents.In cattle, the gene for hornless (H) is dominant to the gene for horned (h), the gene for black (B) is dominant to that of red (b), and the gene for white face, or Hereford spotting, (S) is dominant to that for solid color (s). A cow (female) that is heterozygous for all traits is inseminated by a bull (male) of the genotype bbhhSs. What is the probability of obtaining a calf that is a black, hornless bull with Hereford spotting?
- Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%Albinism in humans is inherited as a simple recessive trait.Determine the genotypes of the parents and offspring for the following families. When two alternative genotypes are possible,list both.(a) Two parents without albinism have five children, four withoutalbinism and one with albinism.(b) A male without albinism and a female with albinism havesix children, all without albinism.Hemophilia is a sex-linked trait where XH gives normal blood clotting and is dominant to the hemophilia allele X h Identify the genotypes of… 1) a woman with normal blood clotting whose father had hemophilia 2) a normal man whose father had hemophilia. What is the probability that a mating between these two individuals will produce a child, regardless of sex, that has hemophilia?
- In humans, six fingers (F) is dominant to five fingers (f). Assume both parents are heterozygous for six fingers.d) What is the probability of them having six-fingered children? Five fingered children?In humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.For Dalmatian dogs, the spotted condition is dominant over non-spotted. (a) Using a Punnett square, show the results of a cross between two heterozygous parents. ( please draw the punnet square and write the parent and G and f1: thanks) (b) A spotted female Dalmatian dog mates with an unknown father. From the appearance of the pups, the owner concludes that the male was a Dalmatian. The owner notes that the female had six pups, three spotted and three non-spotted. What are the genotype and phenotype of the unknown male?