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- 2+ d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9) Oke O Ke = = O Ke = 2+ [Mn²+ ][C1₂] [H3O+] * [CI-1² [Mn²+][H₂O][C1₂] 2+ [H³O+][CI¯]²[MnO₂2] [Mn²+ ] [H₂O1] [C1₂] 2+ [H3O+] * [CI-1²[MnO₂]PHOTOSYNTHETIC PIGMENTS 1.6 0.7 Qy D 1.4 CH. 0.6 1.2 Soret 0.5 A N- 0.4 0.8 H COOCH3 0.3 0.6 phytyl bacteriochlorophyll a 0.2- 0.4 0.1 0.2 - 300 400 500 600 700 800 700 750 800 850 900 2 (nm) 2 (nm) Figure 4.7 Absorption (left) and fluorescence (right) spectra of bacteriochlorophyll a in diethyl ether. 5. Look at this figure from Blankenship's book, Molecular Mechanisms of Photosynthesis. You can see the structure for bacteriochlorophyll a, along with its absorption spectrum. a. What is the molecular shape around the labeled carbon atom? b. What is the hybridization around that same carbon? c. Based on this structure, would you expect this molecule to absorb light in the visible spectrum? Why or why not? Absorbance Fluorescence (Arbitrary units)B12 H₂O C8H1402 NaOH PCC CH₂C₁₂ NaOCH3 CH3OH
- P1V1/T1=P2V2/T22. Run V (NH4)2S₂08 (mL) 20.00 20.00 10.00 5.00 20.00 15.00 1 2 3 4 5 6 [S₂082-] (mol/L) 0.04 0.04. 0.02 0.01 10.09 10.03. VKI (mL) 20.00 10.00 20.00 20.00 8.00 15.00 [1-] (mol/L) 0.08 0.07 0.08 0.08 0.032 V Na₂S₂03 (mL) 10.00 10.00 10.00 10.00 10.00 10.00 [S₂032-] (mol/L) 6.001 0.001 0.001 10.001 0.001 0.001 These calculated concentrations should be entered in the Data Table for this experiment for runs 1-6. To calculate the concentration of [12], use Equation (3) and the concentration of [S₂03²]. In a constant-temperature run described in the procedure section of this experiment, the solution turned blue in 50 s. a) Consider the concentration of [S₂032] in the mixed solution shown in the las column of the table from the previous exercise. Calculate the concentration c [12] final formed in this reaction. b) Calculate the rate of the reaction.2 K₂Cr₂O7 (aq) + 8 H₂SO4 (aq) + 3 C₂H5OH(aq) --> 2 Cr₂(SO4)3 (aq) + 2 K₂SO4 (aq) + 3 CH3COOH (aq) + 11 H₂O (1) The above reaction is what occurs in a breathalyzer test. The ethanol (MM = 46.08 g/mol) reacts with the dichromate ion in potassium dichromate (MM = 294.20 g/mol) to produce the green chromate ion in chromium sulfate (MM = 392.21 g/mol). The sample is analyzed in a hand-held spectrophotometer, and the amount of light transmitted is converted into an electrical signal. The signal is then converted to an absorbance value which is proportional to the amount of ethanol in a sample. Calculate the grams of chromium sulfate formed from 0.0250 g ethanol. Enter the value with no units.
- Relative Abundance *(p) 100 80 60 40 20 57 M (136) I 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100 105 110 115 120 125 130 135 140 m/zoverall aden fn tereactiorabwe! .20 what is te overall aae for tereactrobre! 200 0.00 8.00xl0 1. 0. 1000 200x1o? Trual A +BSAB On 122/ 2 93% 5. Identify O to Z CI AICI Y SO3, Br2 HF H2SO4 FeBr3 CI V CICH CH HNO3 W AICI AICI, H,SO4 H,SO4, A Brz S,T 2.H20 uv R CHCH3 CH U 1. AICI 2. HO CHCH HO. CH, 8:29 PM A ENG 30/3/2021