2+d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9)OkeO Ke==O Ke =2+[Mn²+ ][C1₂][H3O+] * [CI-1²[Mn²+][H₂O][C1₂]2+[H³O+][CI¯]²[MnO₂2][Mn²+ ] [H₂O1] [C1₂]2+[H3O+] * [CI-1²[MnO₂]

Answered: Image /qna-images/answer/e9d17a2d-bf45-488e-99e8-2efe4584c205.jpg

2+ d. 4H3O+ (aq) + 2Cl¯ (aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (g) 2+ [Mn²+ ] [C1₂] [H₂O+]*[C1-1² 2+ Mn²+ [H₂O][C1₂] O Ke Kc = Oke = [H3O+][CI]²[MnO₂] [Mn²+ ] [H₂O] [C1₂] [H3O+]*[C1-1² [MnO₂] H₂

2+ d. 4H3O+ (aq) + 2Cl¯ (aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (g) 2+ [Mn²+ ] [C1₂] [H₂O+][C1-1² 2+ Mn²+ [H₂O][C1₂] O Ke Kc = Oke = [H3O+][CI]²[MnO₂] [Mn²+ ] [H₂O] [C1₂] [H3O+][C1-1² [MnO₂] H₂

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter2: Atomic Structure And Periodicity

Section: Chapter Questions

Problem 133E

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Question

2+
d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9)
Oke
O Ke
=
=
O Ke =
2+
[Mn²+ ][C1₂]
[H3O+] * [CI-1²
[Mn²+][H₂O][C1₂]
2+
[H³O+][CI¯]²[MnO₂2]
[Mn²+ ] [H₂O1] [C1₂]
2+
[H3O+] * [CI-1²[MnO₂]

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