Figure Q2 shows discrete locations of sampled soil electrical conductivity (dS/m). Estimate the magnitude of electrical conductivity at points P, R and T using inverse distance weighting 24 24 Estimate the accuracy of the estimation based on R² if the actual values at P is 5.2 dS/m, at 11 dS/m, and 6.9 dS/m at R 21 12 18 15 12 11 9 6 3 3 1.5 23 R 0 3 6 9 50 17 T 12 12 15 18 Figure Q2 24 21 24

Figure Q2 shows discrete locations of sampled soil electrical conductivity (dS/m). Estimate the magnitude of electrical conductivity at points P, R and T using inverse distance weighting 24 24 Estimate the accuracy of the estimation based on R² if the actual values at P is 5.2 dS/m, at 11 dS/m, and 6.9 dS/m at R 21 12 18 15 12 11 9 6 3 3 1.5 23 R 0 3 6 9 50 17 T 12 12 15 18 Figure Q2 24 21 24

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.5P: To determine the thermal conductivity of a structural material, a large 15-cm-thick slab of the...

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i. Derive the linear and quatratic approximation of the below resistance temperature readings(temperature from 40 °c to 80 °c). (. ii. find out the resistance of RTD at a temperature of 200°c using linear approximation? ( Temperature 40 45 50 55 60[TO] 65 70 75 80 Resistance ohm 115.239 120.521 167.096 254.966 384.13 554.587 766.34 1019.38 1313.724
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We performed the experiment to measure the thermal conductivity of 2 materials (Brass & Steel) in the laboratory and measured the following tabulated values: Material 1 - BRASS (Diameter = 25mm) Power Temperature (°C) Q' (W) 2 3 4 6 7 8 1 5 9 14.6 78.9 77.5 76 50.2 46.7 42.4 36.1 34.6 33.6 Material 2 - STEEL (Diameter = 25mm) Power Temperature (°C) 7 Q' (W) 14.25 2 3 1 9 88.6 87.4 85 34.1 33.4 32.7 CALCULATE THE FOLLOWING: MATERIAL 1 - BRASS Calculation for Brass Quantities Calculated Values Power (Q') W Area of cross section (A) m2 Difference in Temperature between two points (AT) °C Difference in distance between two points (Ax) m Thermal conductivity of brass (k,) W/m'C MATERIAL 2 - STEEL Calculation for Steel Quantities Calculated Values Power (Q') W Area of cross section (A) m? Difference in Temperature between two points (AT) "C Difference in distance between two points (Ax) m Thermal conductivity of steel (k,) W/m°C
explains how the two methods of parameter estimation, namely the method of parameter estimation and the method of moments and percentile matching, are used to fit distributions to data for actuarial calculations.
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The heat transfer conducted through material is calculated from the equation: Q = KX AXTD/L Where K: Conductivity of material A: Area of heat transfer TD: Temperature difference across material L: Thickness of material A student measures the area, thickness and temperature difference and assumes that the error in conductivity is negligible. The student also estimates the uncertainty range for each variable. In estimating the maximum possible value of Q, the student should use the following formula: A B Q max= K x A max x TD max / L max Q max= K x A max x TD max / L nom Q max= Q nominal + dQ/dLmin Q max= K x A max x TD max / L min
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