Problem 4 Buoyancy A lock of mass 30 kg and volume 0.025m² is allowed to sink in water as shown below. A cylindrical rod of mass 1.25 kg, 5 m long, and 25 cm² in cross-section is attached to the weight and to the wall. 1. What will the angle be for equilibrium? 2. If the mass M is released from the road at equilibrium, how much of the rod will remain submerged? 0.25 m 5 m M = 30 kg V=0.025 m³ Figure 4: Lock sinking in water is attached to a wall with the use of a cylindrical rod

Problem 4 Buoyancy A lock of mass 30 kg and volume 0.025m² is allowed to sink in water as shown below. A cylindrical rod of mass 1.25 kg, 5 m long, and 25 cm² in cross-section is attached to the weight and to the wall. 1. What will the angle be for equilibrium? 2. If the mass M is released from the road at equilibrium, how much of the rod will remain submerged? 0.25 m 5 m M = 30 kg V=0.025 m³ Figure 4: Lock sinking in water is attached to a wall with the use of a cylindrical rod

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter4: Coplanar Equilibrium Analysis

Section: Chapter Questions

Problem 4.126P: The center of gravity of the nonhomogeneous bar AB is located at G. Find the angle at which the bar...

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Question

Problem 4
Buoyancy
A lock of mass 30 kg and volume 0.025m² is allowed to sink in water as shown below. A cylindrical
rod of mass 1.25 kg, 5 m long, and 25 cm² in cross-section is attached to the weight and to the
wall.
1. What will the angle be for equilibrium?
2. If the mass M is released from the road at equilibrium, how much of the rod will remain
submerged?
0.25 m
5 m
M =
30 kg
V=0.025 m³
Figure 4: Lock sinking in water is attached to a wall with the use of a cylindrical rod

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