An automatic titration of Cola product was analyzed and the following results were produced: Volume of Standardized NaOH Titrant used to achieve the first equivalence point in titration: Trial #1: 1.300 mL Trial #2: 1.137 mL Trial #3: 1.140 mL  May you explain why trial #1 was skewed; for example, if pipetting of the 25.00 mL was done incorrectly, how would the molarity change if the volume examined was supposed to be 24.50 mL?

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Author:Steven S. Zumdahl
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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 14Q: Consider the following four titrations. i. 100.0 mL of 0.10 M HCl titrated by 0.10 M NaOH ii. 100.0...
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An automatic titration of Cola product was analyzed and the following results were produced:

Volume of Standardized NaOH Titrant used to achieve the first equivalence point in titration:

Trial #1: 1.300 mL

Trial #2: 1.137 mL

Trial #3: 1.140 mL 

May you explain why trial #1 was skewed; for example, if pipetting of the 25.00 mL was done incorrectly, how would the molarity change if the volume examined was supposed to be 24.50 mL?

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