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- 2. A method for analysis of codeine in prescription drugs yielded the following results when applied to a codeine- free blank: 0.01, -0.2, 0.3, 0.2, 0.0, -0.1 mg codeine. Calculate the detection limit (in terms of miligrams in codeine) at 99% confidence level, based upon the mean.Using the data table given below, calculate the molar concentration for a sample dye solution with a measured absorbance of 0.304. (Hint: Use linear regression analysis.). Final answer in 3 significant figures. Determination of Dye Concentration Solution Dye concentration (mM) Absorbance at 520 1 2.50 0.014 5.00 0.176 7.50 0.397 4 10.00 0.611 12.50 0.829The detecton limits reported for Al with ICP-AES and GF-AAS are 2 ppb and 5 picograms, respectivly. If we assume that a 20 microliter sample volume is used for the GF-AAS determination, which method has the lower detection limit? (1 picogram = 10-12 gram.)
- 1. Summarize the steps performed when using an analytical balance. 2. How could you distinguish a problem with a balance from a user technique issue using the collected statistics? 3. Matt weighed a crucible three times and calculated a mean mass of 12.3453 g with a standard deviation of 0.0002 g, while Sunil's result for the same crucible was 12.3448 g with a standard deviation of 0.0003 g. Do their results agree? Why or why not? 4. Next week, you will use the dried NaCl to create a solution. Why is it beneficial to dry any hydroscopic solid prior to weighing out the solid to make a solution? 5. If you wanted to accurately prepare 500 mL of a 1.500 M solution of NaCl, how would you do this? Include the mass of NaCl needed as well as all tools used in preparing this solution.You find that for your analysis, your response factor (adjusted for internal standard) for a particular analyte was 0.0104 ppm. When you run a sample mixture, the integration for that component is 2,186, and the integration for the internal standard is 14,139. What is the concentration of the component in ppm? (Enter the numerical value without units.)A/ The following results were obtained in the replicate determination of the lead content of a blood sample (0.752, 0.756, 0.752, 0.751 and 0.760 )ppm. Calculate the mean, standard deviation, relative standard deviation%, median, variance and confidence limits at t=1.9 of this set of data.
- what can be an analyte for using internal standard? sample: vegetable oil containing ethyl oleate, IS: Ethyl oleate. what should be analyte here (what mixture composions) to use for internal standard method and calibration?Felodipine calcium channel blocker standard (0.251mg/ml) and felodipine sample (0.245mg/ml) solutions were prepared and injected to the HPLC. The peak area of felodipine standard is 275428 and the sample is 272982. The potency (purity) of felodipine standard is 98.9%. What is the assay percentage of felodipine? a. 102.23 b. 98.71 c. 101.07 d. 100.42Analysis of an unknown plant extract yield two peaks X and Y in a chromatogram, 15.65 and 17.03 min respectively in a 30.0 cm column. The peak base width for X is 1.06 and 1.15 for Y. The analysis gave a column resolution equal to- 1.38 1.25 0.31 A detector applicable for the analysis of environmental samples especially for the detection and quantitative determination of chlorinated insecticides ECD FID TCD Which of the following statements is true for the variables that affect column performance? Increasing the number of plates in the column improves resolution Decreasing the retention factor increases resolution Increasing the plate height improves resolution
- The same chloride analysis but using a new method for which the standard deviation was not known, gave the following replicate results, mean and estimated standard deviation: Chloride (ppm) = 346, 359, 350; Mean = 351.67 ppm; Standard deviation = 6.66ppm. Solve for the CI for the 3 determinations at 95% probability level.Retention time is the time taken for the mobile phase to reach the detector. True False