. An interesting mutation in lacI results in repressorswith 110-fold increased binding to both operator andnonoperator DNA. These repressors display a “reverse”induction curve, allowing β-galactosidase synthesis inthe absence of an inducer (IPTG) but partly repressingβ-galactosidase expression in the presence of IPTG. Howcan you explain this? (Note that, when IPTG binds a repressor, it does not completely destroy operator affinity,but rather it reduces affinity 110-fold. Additionally, ascells divide and new operators are generated by thesynthesis of daughter strands, the repressor must findthe new operators by searching along the DNA, rapidlybinding to nonoperator sequences and dissociating fromthem.)

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter10: From Proteins To Phenotypes
Section: Chapter Questions
Problem 13QP: Suppose that in the formation of phenylalanine hydroxylase mRNA, the exons of the pre-mRNA fail to...
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. An interesting mutation in lacI results in repressors
with 110-fold increased binding to both operator and
nonoperator DNA. These repressors display a “reverse”
induction curve, allowing β-galactosidase synthesis in
the absence of an inducer (IPTG) but partly repressing
β-galactosidase expression in the presence of IPTG. How
can you explain this? (Note that, when IPTG binds a repressor, it does not completely destroy operator affinity,
but rather it reduces affinity 110-fold. Additionally, as
cells divide and new operators are generated by the
synthesis of daughter strands, the repressor must find
the new operators by searching along the DNA, rapidly
binding to nonoperator sequences and dissociating from
them.)

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