Computer Systems: A Programmer's Perspective (3rd Edition)
3rd Edition
ISBN: 9780134092669
Author: Bryant, Randal E. Bryant, David R. O'Hallaron, David R., Randal E.; O'Hallaron, Bryant/O'hallaron
Publisher: PEARSON
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Chapter 4, Problem 4.52HW
The file seq-full.hcl contains the HCL description for SEQ, along with the declaration of a constant IIADDQ having hexadecimal value C, the instruction code for iaddq. Modifythe HCL descriptions of the control logic blocks to implement the iaddq instruction, as described in Practice Problem 4.3 and Problem 4.51.See the lab material for directions on how to generate a simulator for your solution and how to test it.
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2. Design a circuit to implement the following pair of Boolean equations:
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Task 3.1
Implementation of Combination Logic Circuit using PLA
Like ROM, PLA can be mask-programmable or field-programmable. With a mask-programmable PLA, the user must submit a PLA program table to the manufacturer. This table is used by the vendor to produce a user-made PLA that has the required internal paths between inputs and outputs. A second type of PLA available is called a field-programmable logic array or FPLA. The FPLA can be programmed by the user by means of certain recommended procedures. FPLAs can be programmed with commercially available programmer units.
,As mentioned earlier, user has to submit PLA program table to the manufacturers to get the user-made PLA. Let the students to try how to determine PLA program table with the help of a question.Draw a PLA circuit to implement the logic functions A'BC + AB'C + AC' and A'B'C' + BC.
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Chapter 4 Solutions
Computer Systems: A Programmer's Perspective (3rd Edition)
Ch. 4.1 - Prob. 4.1PPCh. 4.1 - Prob. 4.2PPCh. 4.1 - Prob. 4.3PPCh. 4.1 - Prob. 4.4PPCh. 4.1 - Prob. 4.5PPCh. 4.1 - Prob. 4.6PPCh. 4.1 - Prob. 4.7PPCh. 4.1 - Prob. 4.8PPCh. 4.2 - Practice Problem 4.9 (solution page 484) Write an...Ch. 4.2 - Prob. 4.10PP
Ch. 4.2 - Prob. 4.11PPCh. 4.2 - Prob. 4.12PPCh. 4.3 - Prob. 4.13PPCh. 4.3 - Prob. 4.14PPCh. 4.3 - Prob. 4.15PPCh. 4.3 - Prob. 4.16PPCh. 4.3 - Prob. 4.17PPCh. 4.3 - Prob. 4.18PPCh. 4.3 - Prob. 4.19PPCh. 4.3 - Prob. 4.20PPCh. 4.3 - Prob. 4.21PPCh. 4.3 - Prob. 4.22PPCh. 4.3 - Prob. 4.23PPCh. 4.3 - Prob. 4.24PPCh. 4.3 - Prob. 4.25PPCh. 4.3 - Prob. 4.26PPCh. 4.3 - Prob. 4.27PPCh. 4.4 - Prob. 4.28PPCh. 4.4 - Prob. 4.29PPCh. 4.5 - Prob. 4.30PPCh. 4.5 - Prob. 4.31PPCh. 4.5 - Prob. 4.32PPCh. 4.5 - Prob. 4.33PPCh. 4.5 - Prob. 4.34PPCh. 4.5 - Prob. 4.35PPCh. 4.5 - Prob. 4.36PPCh. 4.5 - Prob. 4.37PPCh. 4.5 - Prob. 4.38PPCh. 4.5 - Prob. 4.39PPCh. 4.5 - Prob. 4.40PPCh. 4.5 - Prob. 4.41PPCh. 4.5 - Prob. 4.42PPCh. 4.5 - Prob. 4.43PPCh. 4.5 - Prob. 4.44PPCh. 4 - Prob. 4.45HWCh. 4 - Prob. 4.46HWCh. 4 - Prob. 4.47HWCh. 4 - Prob. 4.48HWCh. 4 - Modify the code you wrote for Problem 4.47 to...Ch. 4 - In Section 3.6.8, we saw that a common way to...Ch. 4 - Prob. 4.51HWCh. 4 - The file seq-full.hcl contains the HCL description...Ch. 4 - Prob. 4.53HWCh. 4 - The file pie=full. hcl contains a copy of the PIPE...Ch. 4 - Prob. 4.55HWCh. 4 - Prob. 4.56HWCh. 4 - Prob. 4.57HWCh. 4 - Our pipelined design is a bit unrealistic in that...Ch. 4 - Prob. 4.59HW
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- The program of problem (2) of HW (2) took 10 instructions to verify. Try to realize the same result using least number of instructions.arrow_forwardTask In your group, design and simulate a combinational logic circuit that consists of three or four inputs and at most three outputs. You are required to come up with your own problem and solution, which can by anything related to the environment, relationships, people, vehicles, machines, etc. You need to perform the following: > In your group, brainstorm a suitable problem to be solved > Devise a concise description of the problem > Draw a block diagram of the problem > Develop the truth table for the problem > Solve the minimum expression for the problem using K-Map Implement the logic circuit using basic gates > Realize your design using the Intel Quartus Prime software by schematic entry • Create a new project in Quartus II • Create a new Block Diagram/Schematic File and draw your circuit • Compile your design • Perform a timing simulation of your design > Verify that your system functions correctly Submission Each group will need to submit a report (at E-learning website) which…arrow_forwardGoal AIM/OBJECTIVE (similar to the manual): This is an exercise in designing combinational circuits that can perform 4bit Full Adder and Half Adder. Write a Verilog Behaviour model program for 4bit Full Adder and Half Adder with truth table and circuit diagram.arrow_forward
- Task: Draw the State Diagram for the Moore Sequence Detector FSM. How many states have the New State diagram? Given VHDL Code for the Moore Sequence Detector FSM: LIBRARY ieee;USE ieee.std logic 1164.all; ENTITY Seq_Detector_Moore ISPORT ( Clock : IN STD_LOGIC ;Resetn : IN STD _LOGIC ;w : IN STD_LOGIC ;z : OUT STD _LOGIC ) ;END Seq_Detector_Moore; ARCHITECTURE Behavior OF Seq_Detector_Moore ISTYPE state _type IS ( A, B, C) ;SIGNAL current _state, next _state : state _type;BEGIN --next state decoderProcess (current_state, w)BEGINCASE current_state IS WHEN A =>IF w = ’1’ THEN next _state <= A ;ELSE next _state <= B ;END IF ; WHEN B =>IF w = ’1’ THEN next _state <= A ;ELSE next _state <= C ;END IF ; WHEN C =>IF w = ’1’ THEN next _state <= A ;ELSE next _state <= C ;END IF ; WHEN OTHERS =>next_state<= A ; -- go back to the initial stateEND CASEEND PROCESS ; --state memory (FFs)PROCESS ( Clock, Resetn )BEGINIF Resetn = ’1’ THENcurrent_state <=…arrow_forwardDraw state diagram for this codearrow_forwardFACTS: In Module 3, you have learned about Op-Amps like Inverting and Non-Inverting Amplifier and many more, one of the topics in Module 3 is the Integrator and Differentiator. An operational amplifier (op-amp) integrator is an operational amplifier circuit that performs the mathematical operation of integration with respect to time-this means the output voltage is proportional to the input voltage integrated over time. A differentiator is an op amp-based circuit, whose output signal is proportional to the differentiation of the input signal. An op-amp differentiator is basically an inverting amplifier with a capacitor of suitable value at its input terminal. The electric potential of inverting terminal is also zero, as the opamp is ideal. QUESTION: Answer the ff. 1. What are the problems in an ordinary op-amp integrator? 2. Why op-amp integrator output is linear? 3. What are the problems in an ordinary op-amp differentiator? 4. What are the advantages of integrator and differentiator…arrow_forward
- Figure Q7 describes a Linear Feedback Shift Register (LFSR). Draw the equivalent schematic diagram of the system based on an off-the-shelf shift register, clearly showing the number of exclusive-OR gates needed to construct it. LIBRARY ieee; USE ieee.std logic_1164.all; entity lfsr is CLK, RESET: in STD LOGIC; Q: out STD LOGIC_VECTOR (5 downto 0) ); port ( end lfsr; architecture behavior of lfsr is begin process (CLK,RESET) begin if RESET='1' then Q <= "000001"; else Q <= ( Q(3) xor Q(2) xor Q(0) ) & Q(5 downto 1); end if; end process; end behavior;arrow_forwardWrite the Boolean algebra expressions and simplify using Karnaugh map for the following table of combinations, where A, B and C are inputs and X, Y are outputs. Draw the schematics, compile and simulate the circuit using Altera Quartus software. Turn in the schematics and the waveform simulation diagram of the design (snapshots copied in PowerPoint or Word and saved as PDF files, no jpeg or other picture files). A C Y 1 1 1 1 1 0. 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1arrow_forwardWhat is the smallest number of states in a Moore machine for which a Mealy machine could have fewer states? a. Two, since there could be a one-state Mealy machine that might do the same thing. b. Three, since there could be a simple Moore machine that went to one of two different states and always returned to the original state after that. For such a simple machine, a two-state Mealy machine is possible. c. You need at least four states to exploit the advantages of a Mealy machine over a Moore machine.arrow_forward
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