Exception handling: In Java, the exception is an object used to signal the unexpected error occurred during a program execution. Exception is the error, which arises at run time and such errors can be handled in Java by exception handling. Runtime exception: The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on. Some of runtime exceptions such as, ArithmeticException NullPointerException IndexOutOfBoundsException IllegalArgumentException

Question

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Answer 1

Question

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

I am getting this error with the EXCEPTION

Select the statement that is false regarding file guarding. Group of answer choices: In your .h files all code should be contained within the guards. It restricts the scope of a namespace, which prevents namespace pollution. If used properly it prevents redefinitions of classes/functions. It is an instruction to the preprocessor. It must make use of a unique identifier.

INSTRUCTIONS: Write a C++ script/code to do the given problem. Write a class called profileID, which has data members firstName,lastName, age, birthday and ageCompany (the age when you entered in the company). Remember to use set and get methods to access the data members this time. Also, write another class called bonusAward that has a method getBonus()with arguments yos and etype which are both integer data types. This method calculates the bonus received by an employee using this formula: yos*1000 + etype*1000. Write two derived classes, ASE and SE, using multiple inheritance usingprofileID and bonusAward as parent classes. Both classes must have amethod named getyos()that returns the yos of an employee using the formula age–ageCompany; and a method named getetype() which returns a constant based on the employee type. For ASE, the constant is 10 while for SE that constant is 20. Last, write a main program where you instantiate ASE as employee1 and SE as employee2. Get their…

Answer 2

Question

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Answer 6

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

Answer 7

Chapter 12.3, Problem 12.3.2CP

(a)

Program Plan Intro

Exception handling:

In Java, the exception is an object used to signal the unexpected error occurred during a program execution.

Exception is the error, which arises at run time and such errors can be handled in Java by exception handling.

Runtime exception:

The runtime exceptions are indicated in RuntimeException class that defines the errors in programs such as out of bounds array, numeric errors, and so on.

Some of runtime exceptions such as,

ArithmeticException

NullPointerException

IndexOutOfBoundsException

IllegalArgumentException

Answer 8

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

Answer 9

(b)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

Answer 10

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

Answer 11

(c)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the string variable

String s = "abc";

//Display the result

System.out.println(s.charAt(3));

}

}

Explanation:

In the above code,

In the main function,

Declare and i...

Answer 12

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

Answer 13

(d)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

Answer 14

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

Answer 15

(e)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

Answer 16

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Answer 17

(f)

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 21

Ch. 12.2 - Prob. 12.2.1CP Ch. 12.2 - Prob. 12.2.2CP Ch. 12.2 - Prob. 12.2.3CP Ch. 12.2 - Prob. 12.2.4CP Ch. 12.2 - Prob. 12.2.5CP Ch. 12.2 - Show the output of the following code:Ch. 12.3 - Prob. 12.3.1CP Ch. 12.3 - Prob. 12.3.2CP Ch. 12.4 - Prob. 12.4.1CP Ch. 12.4 - Prob. 12.4.2CP

Solution Summary: The author explains Java's exception handling. Runtime exceptions are defined in the runtimeException class that defines the errors in programs such as out of bounds array, numeric errors, etc.

Concept explainers

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

Explanation of Solution

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = new Object();

//Initialize the object to string variable

String d = (String)o;

}

}

Explanation:

In the above ...

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

Explanation of Solution

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...

Want to see the full answer?

Chapter 12 Solutions

Solution Summary: The author explains Java's exception handling. Runtime exceptions are defined in the runtimeException class that defines the errors in programs such as out of bounds array, numeric errors, etc.

Concept explainers

Explanation of Solution

Output of code: The given code is, //Class definition class Test { // Main function public static void main(String args[]) { //Declare the array variable int[] list = new int[5]; //Display the result System.out.println(list[5]); } } Explanation: In the above code, In t...

Explanation of Solution

Explanation of Solution

Output of code: The given code is, //Class definition class Test { // Main function public static void main(String args[]) { //Create the object for Object class Object o = new Object(); //Initialize the object to string variable String d = (String)o; } } Explanation: In the above ...

Explanation of Solution

Output of code: The given code is, //Class definition class Test { // Main function public static void main(String args[]) { //Create the object for Object class Object o = null; //Convert "o" into string and then display it System.out.println(o...

Explanation of Solution

Output of code: The given code is, //Class definition class Test { // Main function public static void main(String args[]) { //Divide the 1.0 by 0 and then display the result System.out.println(1.0/0); } } Explanation: In the above...

Want to see the full answer?

Chapter 12 Solutions

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Declare the array variable

int[] list = new int[5];

//Display the result

System.out.println(list[5]);

}

}

Explanation:

In the above code,

In t...

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Create the object for Object class

Object o = null;

//Convert "o" into string and then display it

System.out.println(o...

Output of code:

The given code is,

//Class definition

class Test

{

// Main function

public static void main(String args[])

{

//Divide the 1.0 by 0 and then display the result

System.out.println(1.0/0);

}

}

Explanation:

In the above...