(a)
Find the instantaneous power delivered to the
(a)
Answer to Problem 1E
The instantaneous power delivered to the
Explanation of Solution
Calculation:
Refer to the figure given in the question.
Consider the expression of instantaneous power delivered to the resistor.
Here,
Find the voltage across
Substitute 9 V for
Substitute
Since the power value is independent to the time. Hence, the instantaneous power delivered to the resistor is same (3.24 W) for all values of time.
Conclusion:
Thus, the instantaneous power delivered to the
(b)
Find the instantaneous power delivered to the
(b)
Answer to Problem 1E
The instantaneous power delivered to the
t in s | |
0 | |
1 | |
2 |
Explanation of Solution
Calculation:
Substitute
Substitute
The power values for various values of time are tabulated below.
Table 1
t in s | |
0 | |
1 | |
2 |
Conclusion:
Thus, the instantaneous power delivered to the
(c)
Find the instantaneous power delivered to the
(c)
Answer to Problem 1E
The instantaneous power delivered to the
t in s | |
0 | |
1 | |
2 |
Explanation of Solution
Calculation:
Substitute
Substitute
Convert
The power values for various values of time are tabulated below.
Table 2
t in s | |
0 | |
1 | |
2 |
Conclusion:
Thus, the instantaneous power delivered to the
(d)
Find the instantaneous power delivered to the
(d)
Answer to Problem 1E
The instantaneous power delivered to the
t in s | |
0 | |
1 | |
2 |
Explanation of Solution
Calculation:
Substitute
Substitute
The power values for various values of time are tabulated below.
Table 3
t in s | |
0 | |
1 | |
2 |
Conclusion:
Thus, the instantaneous power delivered to the
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Chapter 11 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
- For a certain alternating current, i(t), [A] i = 2 ⋅ sin (500 π ⋅ t + ) π, where the time is in seconds. a) Enter the peak value of the current b) Enter the rms value of the current c) Determine the period time d) Enter the frequency of the alternating currentarrow_forward11.75 Consider the power system shown in Fig. 11.90. Calculate: (a) the total complex power (b) the power factor (c) the parallel capacitance necessary to establish a unity power factor O- + 240 V rms, 50 Hz - Figure 11.90 For Prob. 11.75. 80-j50 92 120 + j70 Ω 60+j0 22arrow_forwardThe voltage represented by e = 240 Sin(377t) volts is connected across a 20 ohms resistor. The RMS current indicated by a modern DMM (digital multi-meter) is ... a) 24 A O b) 8.49 A O c) 12 A O d) 6 Aarrow_forward
- For a sinusoidal source with the below voltage and current, plot the instantaneous power for 0.1 sec: v(t) = 15.25 sin(377 t) and i(t) = 11.33 sin(377t - 30°) %3Darrow_forwardEXAMPLE 11.7 Switch S, in Fig. 11.51 has been closed for a long time. At 1 = 0 s, S, is opened at the same instant that S, is closed to avoid an interruption in current through the coil. a. Find the initial current through the coil. Pay particular attention to its direction. b. Find the mathematical expression for the current i, following the closing of switch S,. c. Sketch the waveform for i,. 486 ||| INDUCTORS S (t 0 s) (1 = 0 s) R2 8.2 k I kN 12 mA R, = 2.2 k2 680 mH E 6 V o 000arrow_forwardThe voltage applied to a circuit is given by v(t) = 208 sin(314 rad/st) V. Determine the following: a) The frequency. b) The period of the waveform. c) The amplitude of the instantaneous voltage at 2.5 ms from zero. d) The amplitude of the instantaneous voltage at 2.5 ms after Vmax e) The time it would take to reach 104 V on the first positive half cycle 9.arrow_forward
- Answer 11.30arrow_forwardSolve for the apparent power, average power, reactive power and power factor for each of the following cases. (a) V =180⟨75∘ V rms, I =12⟨90∘ A rms (b) I =20⟨60∘ A rms , Z =100⟨45∘ Ω (c) v(t)=115cos(ωt+10∘) V, i(t)=5cos(ωt−50∘) Aarrow_forwardA supply voltage v given by v = (240 sin 314t + 40 sin 942t + 30 sin 1570t) volts is applied to a circuit comprising a resistance of 12 ohmconnected in series with a coil of inductance 9.55 mH. Determine (a) an expression to represent the instantaneous value of the current, (b) the rms voltage, (c) the rms current, (d) the power dissipated, and (e) the overall power factor.arrow_forward
- Determine the rms values of each of the following (a) v(t) = 100 sin(ωt) V Vrms = 70.7V (b) i(t) = 8 sin(377t) A Irms = 5.656V(c) v(t) = 40 sin(ωt + 40o) V Vrms = 28.28V (d) i(t) = 120 cos(ωt) mA Irms = 84.84A Can you check if my answer is correct?arrow_forwardDetermine the rms values of each of the following (a) v(t) = 100 sin(ωt) V Vrms = 70.7V (b) i(t) = 8 sin(377t) A Irms = 5.656V(c) v(t) = 40 sin(ωt + 40o) V Vrms = 28.28V (d) i(t) = 120 cos(ωt) mA Irms = 84.84A Can you double check if my answer is correct?arrow_forwardSection 11.8 Power Factor Correction 11.69 Refer to the circuit shown in Fig. 11.88. (a) What is the power factor? (b) What is the average power dissipated? (c) What is the value of the capacitance that will give a unity power factor when connected to the load? 120 V rms Z 10 +j122 60 Hzarrow_forward
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