Chemistry
Chemistry
4th Edition
ISBN: 9780078021527
Author: Julia Burdge
Publisher: McGraw-Hill Education
Question
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Chapter 1, Problem 25QP
Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

F=9F5C×(C)+32F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

C=5C9F(F32F)

Expert Solution & Answer
Check Mark

Answer to Problem 25QP

Solution:

a)

35C

b)

11C

c)

39C

d)

1011C

e)

459.67F

Explanation of Solution

a) 95F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

C=5C9F(F32F).

C=5C9F(95F32F)=5C9F×(63F)=35C

Therefore, the temperature in degree Celsius is 35C.

b) 12F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

C=5C9F(F32F).

C=5C9F(95F32F)=5C9F×(20F)=11.11C

Therefore, the answer is 11.11C, which rounds off to 11C.

c) 102F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

C=5C9F(F32F).

C=5C9F(102F32F)=5C9F×(70F)=38.89C

Therefore, the temperature is 38.89C, which rounds off to 39C.

d)A furnace operating at 1852F.

The temperature in Fahrenheit can be converted to degree Celsius as:

C=5C9F(F32F).

C=5C9F(1852F32F)=5C9F×(1820F)=1011.11C

Therefore, the temperature is 1011.11C which rounds off to 1011C.

e) 273.15C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

F=9F5C×(C)+32F.

F=9F5C×(273.15C)+32F=491.67F+32F=459.67F

Therefore, the temperature is 459.67F.

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