Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
In the Snellen visual acuity chart, the letters in the 20/40 line subtend an angle of 3 milliradians with respect to the eye when viewed at a distance of 6 meters ( i.e., approximately 20 feet ). Using the small-angle approximation, calculate the actual height of the 20/40 letter, in units of mm?
-9.22 was the answer I got and it is saying it's wrong. I also tried 1.44E1, -1.44E1, -1.32E1
please include illustrations, i’m having trouble visualizing the main idea.. Thank you! ?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.