y" +2y +5y=4e¹ cos 2t, y(0)= 0, y'(0)=0

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Q: pls answer 3&4

A: As per our guideline, we are supposed to solve only first question. Kindly repost other question as…

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A: Given differential eqyuation  y4-2y''+y=xex We can also write it as D4-2D2+1y=xex

Q: answer part ii and iii..... show proper working

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A: Please find the attached answer

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