Write the expression as a single logarithm. 3(logz-4logy)+2logw
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vv^(1) 2 3 4 Write the expression as a single logarithm. 3(logz-4logy)+2logw
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- (x^2)/2 + (x^3)/3=gx.Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…Given A={1,2,3,4,56}, B= {2,4,5,6} and C= (1,6,7} 1. B' U C'=
- A = {1,2,3} B = {1,2,3} C = {5,6,7} D = {0,1,2,3,4,5} Is A = C?What is the postfix form of the expression ((x + y) ^ 2) + ((x − 4)/3)? *e(-x)•(-y) what is the mathematical representation of the formula z=y Va2+b2 Z= y.*exp(x)*(-y)/sqrt(a^2+b*2) O z=y. *exp(-x)*(-y)/sqrt(a^2+b^2) O z-y.*exp(-x)*(-y)/sqrt(a^2)+sqrt(b^2) Z=y. *exp(-x). *(-b)/sqrt(a.^2+b.^2) To show the legend of three functions we can use? * Legend('sin(x)";sin(2x)";sin(0.5x);FontSize',16) Legend(['sin(x)",sin(2x)",sin(0.5x)",FontSize', 16) O Legend({'sin(x)""sin(2x),sin(0.5x)'},"FontSize',16) None of the above. the command that change the image to gray scale is? * rbg2 gray O rgb2 gray rjb2 gray none of the above
- 4. Build CFG to generate all strings of the form 1n 0m 1 n, where m and n are greater or equal to 0. Please demonstrate the derivation of 111000000111function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))A = [1 1; 1 -1];b = [80; 20]; A_inverse = inv(A);x = A\b; disp('A inverse is');disp(A_inverse);disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]); if isequal(round(x), [50; 30]) disp('Success');else disp('Incorrect: Please try again');end. Output matlab. .
- 4. A={3,4}, B={4,5}. An B= AUB= A-B= A OB= AXB=Q4/Full the following blanks (1101 1010)BCD(5211) = ( )BCD(3321)=()EX-3=()16 * (1101 1010)BCD(5211) = (1110 1100)BCD(3321)=(1010110)EX-3= (A6)16 (1101 1010)BCD(5211) = (1110 0111)BCD(3321)=(1011001)EX-3= (56)16 (1101 1010)BCD(5211) = (1101 0111)BCD(3321)=(1011001)EX-3= (2B)16 (1101 1010)BCD(5211) = (1011 1110)BCD(3321)=(1000111)EX-3= (44)16 None of them II1 121 12421 12484 21 1248 16 8 4 2 1 1248 16 32 16 8 4 21 1248 16 32 64 32 16 8 4 2 1 1248 16 32 64 128 64 32 16 8 4 2 1 1248 16 32 64 128 256 128 64 32 16 8 4 2 1 By using nested loops, write the code of this triangularshape.