When titrated in neutral solution with 0.05000 N I, a mixture of As203, As2O5, and inert material requires 20.10 mL. The resulting solution is then acidified, and excess KI is added. The liberated Iz requires 29.92 mL of 0.1500 N Na,S,03. Calculate the sum of the weights of As,03 and As205 in the sample.

When titrated in neutral solution with 0.05000 N I, a mixture of As203, As2O5, and inert material requires 20.10 mL. The resulting solution is then acidified, and excess KI is added. The liberated Iz requires 29.92 mL of 0.1500 N Na,S,03. Calculate the sum of the weights of As,03 and As205 in the sample.

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Chapter18: Electrochemistry

Section: Chapter Questions

Problem 4RQ: Consider the equation G = -nF. What are the four terms in this equation? Why does a minus sign...

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