When chloroethane is treated with lithium metal, as shown below (step 1), an alkyllithium reagent A is produced The alkyllithium reagent A (two equivalent) reacts with copper(1) iodide in diethyl ether to give a Gilman reagent G (step 2) which in turn undergoes coouping reaction with chloropropane to give product P (step 3) (Textbook problem 10-11): CH3CH₂Cl 2A + Cul G + CH₂CH₂CH₂Cl 2Li pentane Ether Ether 0 °C The name of alkyllithium reagent A is Aan alkyllithium reagent G P a Gilman reagent

When chloroethane is treated with lithium metal, as shown below (step 1), an alkyllithium reagent A is produced The alkyllithium reagent A (two equivalent) reacts with copper(1) iodide in diethyl ether to give a Gilman reagent G (step 2) which in turn undergoes coouping reaction with chloropropane to give product P (step 3) (Textbook problem 10-11): CH3CH₂Cl 2A + Cul G + CH₂CH₂CH₂Cl 2Li pentane Ether Ether 0 °C The name of alkyllithium reagent A is Aan alkyllithium reagent G P a Gilman reagent

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter6: Reactions Of Alkenes

Section: Chapter Questions

Problem 6.38P: Reaction of -pinene with borane followed by treatment of the resulting trialkylborane with alkaline...

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Compound P (C2H4) which is an alkene undergoes reaction with HCl to produce compound Q (C2H5Cl). Reaction of compound Q with benzene in the presence of AlCl3 as catalyst produces compound R. Then, nitration of compound R in the presence ofnH2SO4 produces two compounds, S and T. But when compound R is reacted with a hot acidified solution of alkaline KMnO4 gives compound U. Deduce the structure of compounds P to U.
Reaction of -pinene with borane followed by treatment of the resulting trialkylborane with alkaline hydrogen peroxide gives the following alcohol. Of the four possible cis,trans isomers, one is formed in over 85% yield. (a) Draw structural formulas for the four possible cis,trans isomers of the bicyclic alcohol. (b) Which is the structure of the isomer formed in 85% yield? How do you account for its formation? Create a model to help you make this prediction.
A hydrocarbon (X), with the molecular formula: C8H14 is reduced in presence of sodium and liquid ammonia to give the only product (Y) with the molecular formula: C8H16. Compounds X and Y both resulting 2,5-dimethylhexane when treated with hydrogen and platinum catalyst (H2/Pt). As a result of the oxidative cleavage of compound Y (by using KMnO4 / H2SO4), a single carboxylic acid derivative with C4H8O2 molecular formula is formed. Again, as a result of the reaction of Y with perbenzoic acid, the chiral compound C8H14O is observed, but the reaction of compound Y with bromine gives the achiral C8H14Br2 as the product.
A is a compound with molecular formula of C6H10, contains three methylene units. A react with one equivalent of H2 over Pd/C to yield B. A reacts with aqueous acid to form a single product, C. A also undergoes hydroboration/ oxidation to form product D. Ozonolysis of A followed by reaction of dimethylsulfide form E with molecular formula C6H10O2. A react with bromine in dichloromethane form F with molecular formula of C6H10Br2. Draw the reaction scheme for all the reaction mentioned above and suggest structure for A – F.
Hydrocarbon A has the formula C9H12 and absorbs 3 equivalents of H2 to yield B, C9H18, when hydrogenated over a Pd/C catalyst. On treatment of A with aqueous H2SO4 in the presence of mercury(II), two isomeric ketones, C and D, are produced . Oxidation of A with KMnO4 gives a mixture of acetic acid (CH3COOH) and the tricarboxylic acid E. Propose structures for compounds A-D, and write the reactions.
Consider the monosubstituted benzene reagent X. Nitration of X yields product Y. Product Y is analysed by 1H and 13C NMR spectroscopy (see Figures 1 to 4). Determine the structure of X and Y on the basis of the spectral data provided.
Cyclopentene reacts with reacts with ozone in dichloromethane at -78° C. Treatment of the resulting ozonide with zinc in acetic acid or with dimethylsulfide gives A(C3H3O2). Treatment of A with sodium borohydride in ethanol gives B(C3H12O2). Draw the structure of B.
(b) acid, HNO3 to produce compound L. The reaction of compound L with bromine, Br2 in the presence of iron tribromide, FeBr3 produced compound M. Benzene also undergoes Fridel-crafts alkylation reaction with chloroethane, CH;CH2CI using catalyst N to produce compound P. Benzene, CeHe undergoes substitution reaction with concentrated nitric Benzena, CsHe menjalani tindak balas penukargantian dengan asid nitrik, HNO, pekat untuk menghasilkan sebatian L. Tindak balas sebatian L dengan bromin, Brz dengan kehadiran ferum tribromida, FeBrs menghasilkan sebatian M. Benzena juga menjalani tindak balas alkilasi Fridel-crafts dengan kloroetana, CH3CH2CI dengan menggunakan pemangkin N untuk menghasilkan sebatian P. (i) Draw the structural formula of L, M and P. Lukiskan formula struktur bagi sebatian L, M dan P. (ii) State catalyst N. Nyatakan pemangkin N. (iii) Show the formation of electrophile that will be reacted with benzene for the formation of compound P.
Compound A has the formula C8H8. It reacts rapidly with KMN04 to give CO2 and a carboxylic acid, B (C7H602), but reacts with only 1 molar equivalent of H2 on catalytic hydrogenation over a palladium catalyst. On hydrogenation under conditions that reduce aromatic rings, 4, equivalents of H2 are taken up and hydrocarbon C (C8H16) is produced. What are the structures of A, B, and C. .CO.H COH A A B C OH A CO2H A B QUESTION 6
Compound A of molecular formula C8H₁4 is reduced by sodium in liquid ammonia to give compound of molecular formula C8H16. product (Y). Both A and B undergo hydrogenation in the presence of a platinum catalyst to give 2,5- dimethylhexane. Ozonolysis of B with an oxidative workup produces a carboxylic acid of molecular formula C4H8O2. Reaction of B with a peroxyacid gives a chiral C8H₁40 product, but reaction with bromine gives an achiral C8H₁4Br2 product. What are the identities of A and B? 14 A is 2,5-dimethyl-3-hexyne; B is cis-2,5-dimethyl-3-hexene A is 2,5-dimethyl-3-hexyne; B is trans-2,5-dimethyl-3-hexene A is 2,5-dimethyl-1,5-hexadiene; B is 2,5-dimethyl-3-hexyne A is 2,5-dimethyl-2,4-hexadiene; B is cis-2,5-dimethyl-3-hexene
A, a compound with molecular formula C6H10, contains three methylene units. A reacts with one equivalent of H2 over Pd/C to yield B. A reacts with aqueous acid to form a single product, C, and undergoes hydroboration/oxidation to form a pair of enantiomers, D and E. Ozonolysis of A followed by reaction with dimethyl sulfide forms F with molecular formula C6H10O2. Provide structures for A–F.
Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.