When 1-methoxy-2-methylpropene is treated with HCl, the major product is 1-chloro-1-methoxy-2-methylpropane. Although this reaction proceeds via an iconic mechanism, the Cl is ultimately positioned at the less substituted carbon. Draw a mechanism with this outcome and explain why the less substituted carbonation intermediate is more stable. Explanation: The less substituted carbonation has better stabilization because of a. resonance b. electron donation by the methyl groups c. reduced steric hindrance d. electron withdrawal by the methyl groups while the more substituted carbon is only stabilized by: a. resonance b. electron donation by the methyl groups c. reduced steric hindrance d. electron withdrawal by the methyl groups

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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When 1-methoxy-2-methylpropene is treated with HCl, the major product is 1-chloro-1-methoxy-2-methylpropane. Although this reaction proceeds via an iconic mechanism, the Cl is ultimately positioned at the less substituted carbon. Draw a mechanism with this outcome and explain why the less substituted carbonation intermediate is more stable.

Explanation: 

The less substituted carbonation has better stabilization because of 

a. resonance 

b. electron donation by the methyl groups 

c. reduced steric hindrance 

d. electron withdrawal by the methyl groups 

while the more substituted carbon is only stabilized by:

a. resonance 

b. electron donation by the methyl groups 

c. reduced steric hindrance 

d. electron withdrawal by the methyl groups 

1-Methoxy-2-methylpropene
HCI
CI
1-Chloro-1-methoxy-2-methylpropane
Transcribed Image Text:1-Methoxy-2-methylpropene HCI CI 1-Chloro-1-methoxy-2-methylpropane
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