What will be the results of the following crosses, where N is black, n is brown, L is short hair and l is long hair. Make the tables and the corresponding explanation: 1. Crossing a Nnll woman dog with a Nnll dog. 2. Crossing a NnLl woman dog with a NnLl dog 3. Crossing a woman dog nnLl with a dog NNll
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- Name: Genetic Crosses that Involve 2 Traits In rabbits, black hair is dominant to brown hair. Also in rabbits, long straight ears are dominant to floppy ears. These letters represent the genotypes and phenotypes of the rabbits: BB = black hair EE = long ears Ee = long ears ee = floppy ears Bb = black hair bb = brown 1. A male rabbit with the genotype BBee is crossed with a female rabbit with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. How many out of 16 have black hair Be Be Be Be and long ears? How many out of 16 have black hair bE and floppy ears? be How many out of 16 have brown hair and long ears? bE How many out of 16 have brown hair be and floppy ears? 2. Show the cross: GgBb x ggBb How many out of 16 have black hair and long ears? How many out of 16 have black hair and floppy ears? How many out of 16 have brown hair and long ears? How many out of 16 have brown hair and floppy ears?While sitting at home during Movement Control Order (MCO) because of pandemic covid19, observe two different traits of a couple in your family (eg. your mom & dad or your sister & her husband or your brother & his wife, etc). Draw a genetic cross that involves cross of the parents with the chosen 2 pairs of their contracting traits. Imagine that the cross obeys the Mendelian Laws, show the cross and gametes production for each generation (P, F1 and F2). By Using a Punnet square as symbolic representation of the results for the cross, determine the phenotypes, genotypes, phenotypic ratio and genotypic ratio of F2 generation in the family.Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh Ee
- Solve the given Problems: A. The man is heterozygous type B (BO) and the partner is homozygous type A (AA). Do the cross to show how it happens and answer the following: What are the different blood types and the corresponding genotypes of their kids? What is the chance or the probability to have a blood type B child? How about the chance to have a type AB child? If the couple plans to have 3 kids, how many combinations of blood types will be true for their kids? B. The two rabbits with these corresponding genotypes were mated; CCch X CCh . Do the cross and answer the following questions. How many phenotypes will there be for the offspring? How about the genotypes? What is the percentage of agouti offspring to come out? What is/are the other phenotype/s of the offspring besides agouti?Answer the following. Letters only. 1. In mice, black color (B) is dominant over brown (b), and a solid pattern (S) is dominant over white spotted (s). Color and spotting are controlled by genes that assort independently. A homozygous black, spotted mouse is crossed with a homozygous brown, solid mouse. All the F1 mice are black and solid. What are the genotypes of the parents? * a. BBSs and bbss b. BBSs and bbSS c. BbSs and bbSs d. BBss and bbss e. BBss and bbSS f. None of the choices 2. In mice, black color (B) is dominant over brown (b), and a solid pattern (S) is dominant over white spotted (s). Color and spotting are controlled by genes that assort independently. A homozygous black, spotted mouse is crossed with a homozygous brown, solid mouse. All the F1 mice are black and solid. What will be the genotypic probability of the first filial (F1) generation offspring? * a. 100% BBSS b. 100% BbSs c. 50% BBSS and 50% BbSs d. 25% BBSS; 50% BbSs and 25% bbss e. 100% black, solid mice…A. The man is heterozygous type B (BO) and the partner is homozygous type A (AA). Do the cross to show how it happens and answer the following: 1. What are the different blood types and the corresponding genotypes of their kids? 2. What is the chance or the probability to have a blood type B child? 3. How about the chance to have a type AB child?
- The following is the result of a three point cross abc X ABCI will be adding two questions here because I asked two of the same questions twice by accident earlier. A man and a woman do not have hemophilioa, but the womans father did. (Hemophilia is X-linked recessive). a) What is the probability that they will have a child with hemophilia? b) Is it possible for any of their daughters to be affected? Explain. A cross between a horse homozygous for red hair and a horse homozygous for white hair results in offspring with the coat colour called roan. When you look at the fur of the roan offspring you see both red and white hairs. What type of inheritance best explains this? a) blending inheritance b)codominance c)incomplete codominance d)multiple allelesI just want an explanation of what is in bold please. Lab Introduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes The F1 progeny Genotype and Phenotype Cross between two F1 Selfed testcross The F1 gametes The expected F2 results, genotype, phenotype, genotypic ratio, phenotypic ratio. 1.…
- 3) Queen Victoria of England, who ruled from 1837-1901, is believed to have been the carrier of hemophilia. Hemophilia is an X-linked disease in which the blood is unable to form clots. Please make a Punnet Square using the scenario below and answer the following questions. Queen Victoria married a man who did not have the hemophilia trait or disease. What is the likelihood that they would have a child with hemophilia? What is the likelihood that they would have a son with hemophilia? What is the likelihood that they would have a daughter with hemophilia?Genotype HA На hA ha НА НН АА НН Аа Hh AA Hh Aa На НН Аa НН аa Hh Aa Hh aa hA Hh AA Hh Aa hh AA hh Aa ha Hh Aa Hh aa hh Aa hh aa Кey: H = long hair h = short hair A = brown a = green What is the probability that among the first two offspring, one will be short-haired and green- eyed, and the other will be short-haired and brown-eyed? 3/256 3/128 O 1/16 О 3/16Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…