What was the starting alkyne and the corresponding reagents for the formation of (this is acetylide formation):CH;CH2CH2C=C-HH-C=C–H and NaNH2, NH3 , CH3CH2BrBH-C=C–H and NaNH2, NH3 , CH;CH2CH2CH2B.H-C=C-H and NaNH2, NH3, CH3CH2CH,BrDН—СЕС—H and NaNH2, NH3, CH;CH2CH2CH,CH,Br

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What was the starting alkyne and the corresponding reagents for the formation of (this is acetylide formation): CH;CH2CH2C=c-H A H-C=C-H and NaNH2, NH3, CH;CH2B H-C=C-H and NaNH2, NH3, CH;CH2CH2CH2B H-C=C-H and NaNH2, NH3 , CH;CH2CH,Br Н—СС—H and NaNH2, NH3, CH CH2CH2CH-CH-Br

What was the starting alkyne and the corresponding reagents for the formation of (this is acetylide formation): CH;CH2CH2C=c-H A H-C=C-H and NaNH2, NH3, CH;CH2B H-C=C-H and NaNH2, NH3, CH;CH2CH2CH2B H-C=C-H and NaNH2, NH3 , CH;CH2CH,Br Н—СС—H and NaNH2, NH3, CH CH2CH2CH-CH-Br

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter9: Nucleophilic Substitution And Β-elimination

Section: Chapter Questions

Problem 9.39P: Following are diastereomers (A) and (B) of 3-bromo-3,4-dimethylhexane. On treatment with sodium...

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Question

What was the starting alkyne and the corresponding reagents for the formation of (this is acetylide formation):
CH;CH2CH2C=C-H
H-C=C–H and NaNH2, NH3 , CH3CH2Br
B
H-C=C–H and NaNH2, NH3 , CH;CH2CH2CH2B.
H-C=C-H and NaNH2, NH3, CH3CH2CH,Br
D
Н—СЕС—H and NaNH2, NH3, CH;CH2CH2CH,CH,Br

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