What is the mass in grams of precipitate formed when 250.0 mL of 0.160 M ZnCl₂ is mixed with excess KOH in the following chemical reaction? ZnCl₂ (aq) + 2 KOH (aq) → Zn(OH)2 (s) + 2 KCI (aq)

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Chapter4: Chemical Reactions
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Question 1 of 12
What is the mass in grams of
precipitate formed when 250.0 mL
of 0.160 M ZnCl₂ is mixed with
excess KOH in the following
chemical reaction?
1
4
7
+/-
ZnCl₂ (aq) + 2 KOH (aq) → Zn(OH)2
(s) + 2 KCI (aq)
2
5
8
3
60
9
O
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Transcribed Image Text:Question 1 of 12 What is the mass in grams of precipitate formed when 250.0 mL of 0.160 M ZnCl₂ is mixed with excess KOH in the following chemical reaction? 1 4 7 +/- ZnCl₂ (aq) + 2 KOH (aq) → Zn(OH)2 (s) + 2 KCI (aq) 2 5 8 3 60 9 O Submit g Tap here or pull up for additional resources XU x 100
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