What is a primary reason for needing to standardize strong base titrants like NaOH and KOH? 1)Standardization is the process of dissolving NaOH or KOH in aqueous solution. 2)NaOH and KOH are both inexpensive, highly soluble, and easy-to-use bases. 3)Standardization is the process of reacting a strong base like NaOH or KOH with an acid. 4)NaOH and KOH both react with moisture in the air thereby making accurately-determined concentrations of their solutions difficult. 5)NaOH and KOH are not very soluble in aqueous solutions making the concentrations difficult to determine.

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A: Option b is correct.

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Q: Consider the reaction of a 20.0 mL of 0.220 M C₅H₅NHCl (Ka = 5.9 x 10⁻⁶) with 12.0 mL of 0.211 M…

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Q: Do you always have to use a primary standard in the standardization of titrant? Why or why not?

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Q: If you have a 74.0 mL solution of 0.160 M benzoic acid, C6H5 COOH, and it is being titrated with…

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Q: 14 9 Hd 7 A pka of the indicator D C B negligible volume difference Vbase Titration of a Strong Acid…

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Q: Consider the following titrations: i. 100.0 mL of 0.10 M HCl titrated by 0.10 M NaOH ii. 100.0 mL of…

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Q: Match the following terms with their definitions:

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Q: What is a primary reason for needing to standardize strong base titrants like NaOH and KOH?   A…

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Q: Consider the titration of 24.6 ml of 0.200 M HNO2 (Ka = 7.1×10-4) with 0.519 M KOH. What is the…

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A: All the questions have been answered with proper reasons.

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.