What are the phenotypes if a cross between these parents will yield: a. 27 red, 48 pink, 24 white flowered plants________ x_______ b. 18 red and 15 pink flowered plants ________ x________ c. 32 pink and 29 white flowered plants ________ x_______
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- In four o’clock, Mirabilis jalapa, it was found out that the allele W for red flowers is incompletely dominant over that for white, the heterozygous being pink. What are the
phenotypes if a cross between these parents will yield:
a. 27 red, 48 pink, 24 white flowered plants________ x_______
b. 18 red and 15 pink flowered plants ________ x________
c. 32 pink and 29 white flowered plants ________ x_______
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- In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?Petunia flower color is governed by two alleles, but neither allele is truly dominant over the other. Petunias with the genotype RR are red-flowered, those that are heterozygous (RW) are pink, while those with the (WW) genotype have white flowers. This is an example of incomplete dominance. a. If a white-flowered plant is crossed with a red-flowered plant, what is the genotypic ratio of the F1. b. What is the phenotypic ratio of the F1. c. If two of the F1 offspring were crossed, what phenotypes would appear in the F2?. d. What would be the genotypic ratio in the F2 generation?a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
- What is the predicted phenotypic ratio for the offspring of the following cross? Allele phenotypes: R = red, r = white, T = thin leaf, t = broad leaf Cross: RR; Tt x Rr; tt Red with thin leaves ___________ Red with broad leaves ___________ White with thin leaves ___________ White with broad leaves __________ PLEASE show work and give an explanation... Thank you!Consider the Mendelian inherited genes below (complete dominance.) Draw your answer on paper and upload a photo here or complete your answer digitally and upload your file in a common format here. A. Track one gene: Blue bonnet flower color. Dominant allele = blue flowers, B; Recessive allele = white flowers, b Cross: heterozygous plant x homozygous recessive plant Set up and draw the Punnett square for this cross Predict % likelihood of offspring possible genotype & phenotypes B. Track two genes: Bluebonnet flower color and plant height Flower color: blue dominant B, white recessive b Plant height: tall dominant T, short recessive t Cross: heterozygous plant x homozygous recessive plant Set up and draw Punnett square Predict % likelihood of offspring genotypes and phenotypesTall tomato plants are produced by the action of a dominant D allele and dwarf plants by its allele. recessive d. The hair shaft is produced by a dominant H gene and the hairless shaft by its recessive allele h.A test cross was applied to a dihybrid plant and the following results were obtained;b. High-hairy 125c. High non-hairy 115d. Hairy dwarfs 117e. Non-hairy dwarfs 123 a. Diagram the cross indicating the genotype of each parent.b. What are the expected phenotypic proportions showing their absolute frequency?c. Do these loci segregate independently?d. Because?
- T = Tall t = short pollen from a tall pea plant T T eggs from a tall pea plant T TT TT t Tt Tt In the square shown, which of the following is true about the offspring resulting from the cross? Multiple Choice a. Half are expected to be short. b. All are expected to be tall. c. All are expected to be short. d. All are expected to be of medium height.Use the following information to answer the next question. A monohybrid cross of two pure forms of red flowers and white flowers in Mirabilis jalapa plant with genotypes R¡R1 and R2R2 produced all pink flowers. The F2 generation produced a phenotypic and genotypic ratio of 1: 2: 1. Which genetic mechanism can account for these results? O dihybrid cross O incomplete dominance O co-dominance O multiple allelesYou have a purple-flowered pea plant, but you do not know if it is homozygous (PP) or heterozygous (Pp) for flower color because both genotypes result in the same purple phenotype. Purple color allel (P) is dominant over white flower allel (p). What would you do to determine the genotype of flower color of this plant? Lötfen birini seçin: O a. Crossing the plant with homozygous large flowered pea plant (LL) Ob. Crossing the plant with heterozygous purple flowered pea plant (Pp) Crossing the plant with homozygous dominant purple flowered pea plant (PP) d. Crossing the plant with a plant whose genotype is unknown e. Crossing the plant with homozygous recessive white flowered pea plant (pp)
- D D 1 2 d In a particular plant, leaf color is controlled by gene locus D. Plants with at least one allele D have dark green leaves, and plants with the homozygous recessive dd genotype have light green leaves. A true-breeding, dark-leaved plant is crossed with a light-leaved one, and the F1 offspring is allowed to self-pollinate. The predicted outcome of the F2 is diagrammed in the Punnett square shown in the figure, where 1, 2, 3, and 4 represent the genotypes corresponding to each box within the square. Which of the boxes marked 1-4 correspond to plants with a heterozygous genotype? O 1 only O 1, 2, and 3 2 and 3 2, 3, and 4 4) 3.In a species of flowers, blue petals are dominant over purple petals, and a long stem is dominant over a short one. Cross a flower that is heterozygous for both traits with a flower that is homozygous recessive for petal color and homozygous dominant for stem length. Report the genotype and phenotype. *Write your answers in ratio non-reduced form (Example 16:8) Genotype PhenotypeA pea plant believed to be heterozygous was selfed and produced pods with the followingphenotypes: 26 constricted yellow73 constricted green83 inflated yellow251 inflated green a. Using the letters A and B, assign alleles to the different traits.b. Determine whether the ratio of pea pods support the hypothesis that the plant isheterozygous.
