We will examine some human phenotypes that are controlled by a single gene. For each characteristic, you will determine your phenotype, possible genotype(s), and the frequency of your phenotype in the class.
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We will examine some human
- Tongue-rolling: a single gene with two alleles, R and r, determines a person’s ability to roll their tongue into a U shape. A person that cannot roll their tongue is homozygous recessive (rr).
What is your phenotype? _____
What is your genotype(s)? _____
What is the frequency of your phenotype? (show your work)
_________
- Widow’s peak: a single gene with two alleles, W and w. The dominant allele (W) results in a hairline that forms a distinct point in the center of the forehead.
What is your phenotype? _____
What is your genotype(s)? ____
What is the frequency of your phenotype? (show your work)
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- To understand this research, you must be familiar with some basic genetic terminology. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Not all terms will be used. dominant allele phenotype The possession of two different alleles of a particular gene is referred to as Reset Help A variation in a DNA sequence at one particular position is called a heterozygosity genotype recessive allele homozygosity single nucleotide polymorphism The appearance of the organism, its observable traits, are referred to as the A variant of a gene for which an individual must be homozygous in order for it to influence the appearance of the organism is a The set of alleles an organism has for a particular trait is the organism's Submit Request AnswerIn man, muscular dystrophy is a condition in which the muscles waste away during early life and may result in a shorter life expectancy. It is due to a sex-linked, recessive gene. A certain couple has five children – three boys (ages 1yr, 3yrs, and 10yrs old) and two girls (ages 5yrs and 7yrs old). The oldest boy shows the symptoms of this disease. You are their family physician and they come to you for advice. What would you tell them about the chances of their other children developing the disease?Red-green color blindness, in humans, is a sex-linked trait controlled by alleles on the X chromosome. Normal color vision (X+) is dominant to colorblindness (Xc). (NOTE: You could write this as XC for the normal allele and Xc for the recessive colorblind allele. Unfortunately, capital C and lowercase c are hard to tell apart as superscripts, especially in type. I will use C -- "X-plus" -- for the normal allele.) If a colorblind man marries a woman with normal vision and they have a colorblind son, what are the genotypes of the father and the mother?
- Put your thumb up (i.e., the “thumbs up” hand signal). Hypothetically (but not actually), if your thumb is bent then you exhibit the dominant phenotype, and if it is straight then you exhibit the recessive phenotype. Write your phenotype and all of your possible genotype(s) using the correct genetic terminology (do not just write letters like “Ee”). Next, if you had children with someone who showed the dominant phenotype, could these children show the recessive phenotype? Why or why not?While stuck at home in quarantine, several Bi213 students decide to conduct an experiment using their beloved cats. These students learn that a fictional gene "H" correlates with how happy their pets are to have their owners at home more frequently than usual. Cats that are homozygous dominant (HH) or heterozygous (Hh) are very happy to see their owners 24/7. While cats that are homozygous recessive (hh) are starting to miss having the house to themselves. The students collaborate with their professors to genotype the H allele in their cats by sequencing their DNA. They obtain the following data: 8 HH cats, 21 Hh cats, and 84 hh cats. The table below may be helpful. (Observed - Eaреcted)? Σ Еaрected Genotype (О— Е) (0 – E)² (0 – E)²/E Observed Еxpеcted E HH Hh hh x² = %3D df = p = Conduct a chi-square test to determine if this population is in Hardy-Weinberg equilibrium. Enter your chi-square with 2 decimals in the box below.***18. Complete this flowchart to show how different alleles can result in different characteristics. In the DNA, different alleles of a gene have a different sequence of > different sequence of transcription > different sequence of in a protein translation > different structure and function of the protein (e.g. normal enzyme vs. defective enzyme) > different characteristics (e.g. normal color vs. albino) in
- Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___At least two pairs of genes control eye color. Both pairs influence the production of the pigment, melanin, but act independently. One pair of alleles is B (Brown color; dominant) and b (blue color); the other pair is A (pigment production; dominant) and a (no pigment production; albino). The gene pair aais epistatic to (masks) B and b and produces the nonpigmented eyes of the albino. What is the typeof gene interaction that exists between the two gene pairs? Give the genotypes and phenotypes of the possible offspring of the mating bbAa x Bbaa andi ndicate the parental phenotypes. (any method)As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.
- As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! Review the information on Labrador retrievers above. What are the phenotypic ratios of the F1 generation offspring of two dihybrids? Make sure to match the numbers with coat colors (e.g, which number in the ration goes with which color). Use a Punnett square to…You are studying three traits in a goldfish variety; body colour (A or a), tail length (B or b) and shape (C or c). Note: Use the uppercase letters for the alleles associated with the dominant phenotypes and the lowercase letters for the alleles associated with the recessive phenotypes. Assume that each of these traits is regulated by one gene. Photo credit https://www.petmd.com Part A. You mate a gold fish (P1) with a white fish (P2) and obtain 100 fish in F1, of which 50 are gold and 50 are white. Write two sets of the possible genotypes of the parental and the resulting F1 fish by filling in the table below. Sets P1 P2 F1 gold fish F1 white fish 1 2 Part B. You cross a true breeding gold fish having long curly tail (P3) with a true breeding gold fish having short and straight tail (P4). All of the resulting F1 fish have long straight tails. Write the genotype of the parental fish (P3 and P4) using the outlined nomenclature.…Certainly, not all Muppets look like the one shown in the picture below, nor do they all look the same. In fact, there’s a great deal of phenotypic variation in Muppets. Two traits that have been particularly well-studied are curly hair presences and skin color. One individual is a male, and he possesses a green skin and no hair, whereas the female individual possess a curly hair and pink skin. Let’s call the gene controlling skin coloration S and that controlling hair H. In this species, both hair and green skin are recessive traits. Both of the individuals shown are homozygous. 1. What is the genotypes of Miss Piggy: 2. Kermit's Genotype: 3. If these two lovebirds (er, love-muppets?) mated, what would their offspring look like? Describe all phenotype combinations possible and the ratios in which they would occur?