Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R1 = 39kohms %3D 3. R2 = 7kohms 4. RC = 4kohms %3D 5. RE = 1kohms %3D 6. BDC = 149 %3D Solve for: 1. VB = Blank 1 V; 2. VE = Blank 2 V; 3. IE = Blank 3 mA; %3D 4. VCE = Blank 4 V; %3D 5. VC = Blank 5 V:

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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USE 2 decimal places, rio commas. Given: Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R139kohms 3. R2 7kohms 4. RC= 4kohms 5. RE 1 kohms 6. BDC = 149 ** Solve for: 1. VB Blank 1 V. 2. VE Blank 2 V; 3. IE= Blank 3 mA; 4. VCE Blank 4 V; 5. VC Blank
USE APPROXIMATE ANALYSIS
USE 2 decimal places, no commas.
Given:
Voltage-divider biased, npn BJT with
1. VCC = 22V
2. R1 = 39kohms
3. R2 = 7kohms
4. RC = 4kohms
5. RE = 1kohms
6. BDC = 149
Solve for
1. VB = Blank 1 V,
2. VE = Blank 2 V;
3.IE = Blank 3 mA;
4. VCE = Blank 4 V;
5. VC = Blank 5 V
Blank 1
Add your answer
Blank 2
Transcribed Image Text:USE APPROXIMATE ANALYSIS USE 2 decimal places, no commas. Given: Voltage-divider biased, npn BJT with 1. VCC = 22V 2. R1 = 39kohms 3. R2 = 7kohms 4. RC = 4kohms 5. RE = 1kohms 6. BDC = 149 Solve for 1. VB = Blank 1 V, 2. VE = Blank 2 V; 3.IE = Blank 3 mA; 4. VCE = Blank 4 V; 5. VC = Blank 5 V Blank 1 Add your answer Blank 2
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