Vo(s) = S 5+s 3(5+5) 3 V015) = *£$ = (5² +85+18) (5+) s²+85 3 How? 5+85+18 3 3 [S+2.4.5+ 4+2 (S+2)² +2 √₂ √₂ (S+4)² + (12) Vols) = Vols) = vx LIT [eat sinbt] Vo(s) Inverse vo(t) LOT NOCNA SOLT [ 2 (FY (IT) (s+y)² + (√3)²) = (Sta) 45
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- In the figure: R1 = 27.3 Q, R2 = 93.1 Q and R3 = 1571.12 Q, then determine the value of the source current Is. 12 13 RT R1 R2 R3 E 1.33 0.98 1.44 1.73 1.15If a circuit has a resistance of 3002 and a series inductance of 5002, what is the relationship between the applied circuit voltage and the circuit current? The applied voltage lags the circuit current. The phase shift between the circuit voltage and current changes with time. The applied voltage is in phase with the circuit current. The applied voltage leads the circuit cur Previous Page Next Page Page 2 of 10Charging: A 0.2 F capacitor and a 80092 resistor are connected in series with a battery of voltage 10 volts as shown in the figure. E Answer questions 1-5 www R Tim Atte ON
- Q5] find the current of the resistance 1892 if the value of the source is 7.4sin(100πt-44) volt HH 1mF R1 ww 18Q R4 •14Ω 3.9mF 13.100, 78.163⁰ mA O 14.100, 78.163⁰ mA O 15.100, 78.163⁰ mA 0.093H V1Solve for computed VA IR3 using NODAL ANALYSIS R1 – 4.7 kΩ • R2 – 6.8 kΩ • R3 – 10 kΩ • R4 – 22 kΩ • R5 – 33 kΩTake R1= 2ohms
- Q4. Determine the equivalent inductance and equivalent current of the inductive circuit in Figure Q4. If L5 is replaced with a capacitor of 0.5 mF, how would it affect the branch current? The alternating Voltage source has an amplitude of 20 Vm. Vm Sine 50 Hz L1 5 mH L2 3 mH Figure Q4 reee L3 6.6 mH L4 2.8 mH rele L5 7 mHFind the voltage across each inductor for the given circuit using the voltage divider rule. VL1 +m= L₁=10mH Vs=100 V, 60 Hz VL2 +mm- L₂=14mHOne steradian represents (rad)^3 O 2rad O (rad)^2 O none O
- Calculate the output voltage for the circuit given. The value of input voltage can be taken as 2mV, load resistor has a value of 10K Ohm and Beta has a value of 100. You MUST include the value of re' in the calculations. Please make wave-forms at each point. Vcc +20V Rc 3.3 kN C3 33 k2 out I µF RE 330 N ER2 10 ΚΩ RE2 330 2 C2 10 μFSolve for the equivalent inductance at terminals a-b, if L1 = 39 mH and L2 = 98 mH. (Hint: You may add wires and flip the circuit) L1 60 mH 25 mH L2 a o ele ell 30 mH ellDetermine the DC currents (B. Ic and le) and de juncion voltages (VBE, VCE and Vca) mA. Ic ma, E mA VBE= V. VCE Vand VCB Use 2 decimal places. RB Use the following values: VBB = 3V RB = 4 kQ Rc = 166 0 Vcc = 19 V BDC = 70 %3D %3D VCC RC VBB