VertexParabolic ForceDistribution300 N/mProblem TwoThe cantilever beam of the figure has a parabolic distribution of force; the vertex of the parabola is alsonoted there.1. Find the magnitude and direction (up or down) of the single point force which is equivalent to thisparabolic force distribution.2. Locate the line-of-action of this single equivalent point force (i.e., find the "x" coordinate locationwith respect to the point A). -a-Region I¥= Kx²(paiabolie)Region IRegin IAreay = tahKegion IArcar = 응hJr = h!

The equivalent force of any force system is that force that produces the same effect of load…

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Engineering

Mechanical Engineering

Vertex Parabolic Force Distribution AE 300 N/m

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter6: Beams And Cables

Section: Chapter Questions

Problem 6.6P: Find the internal force systems acting on sections 1 and 2.

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Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the shearing and machining process, the material does not undergo up to a failure point as indicated in the stress-strain curve. Hence, the stresses induced during the forming process are greater than yield strength but less than the failure strength of the material. The process does not lead to the loss of material, so it can be said to be an economical process. During forming, the material is subjected to tensile forces, compressive forces, bending, and shearing loading conditions. The material should possess the property of ductility to undergo the forming process.

Question

Vertex
Parabolic Force
Distribution
300 N/m
Problem Two
The cantilever beam of the figure has a parabolic distribution of force; the vertex of the parabola is also
noted there.
1. Find the magnitude and direction (up or down) of the single point force which is equivalent to this
parabolic force distribution.
2. Locate the line-of-action of this single equivalent point force (i.e., find the "x" coordinate location
with respect to the point A).

-a-
Region I
¥= Kx²(paiabolie)
Region I
Regin I
Areay = tah
Kegion I
Arcar = 응h
Jr = h
!

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