Verify the identity. cotangent x equals StartFraction sine 2 x Over 1 minus cosine 2 x EndFractioncot x=sin2x1−cos2x Question content area bottom Part 1 Use the appropriate double-angle formulas to rewrite the numerator and denominator of the expression on the right. For the denominatordenominator, use the double-angle formula that will produce only one term in the denominatordenominator when it is simplified. Part 2 StartFraction sine 2 x Over 1 minus cosine 2 x EndFractionsin2x1−cos2x equals= StartFraction nothing Over 1 minus left parenthesis nothing right parenthesis EndFractionenter your response here1−enter your response here equals= StartFraction nothing Over nothing EndFractionenter your response hereenter your response here Simplify the denominatordenominator. Enter the numeratornumerator found in the previous step. Part 3 The expression from the previous step then simplifies to cotangent xcot x using what? A. Reciprocal Identity B. Even-Odd Identity C. Pythagorean Identity D. Quotient Identity
Verify the identity. cotangent x equals StartFraction sine 2 x Over 1 minus cosine 2 x EndFractioncot x=sin2x1−cos2x Question content area bottom Part 1 Use the appropriate double-angle formulas to rewrite the numerator and denominator of the expression on the right. For the denominatordenominator, use the double-angle formula that will produce only one term in the denominatordenominator when it is simplified. Part 2 StartFraction sine 2 x Over 1 minus cosine 2 x EndFractionsin2x1−cos2x equals= StartFraction nothing Over 1 minus left parenthesis nothing right parenthesis EndFractionenter your response here1−enter your response here equals= StartFraction nothing Over nothing EndFractionenter your response hereenter your response here Simplify the denominatordenominator. Enter the numeratornumerator found in the previous step. Part 3 The expression from the previous step then simplifies to cotangent xcot x using what? A. Reciprocal Identity B. Even-Odd Identity C. Pythagorean Identity D. Quotient Identity
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section: Chapter Questions
Problem 14RE
Related questions
Question
Verify the identity.
cotangent x equals StartFraction sine 2 x Over 1 minus cosine 2 x EndFractioncot x=sin2x1−cos2x
Question content area bottom
Part 1
Use the appropriate double-angle formulas to rewrite the numerator and denominator of the expression on the right. For the
denominatordenominator,
use the double-angle formula that will produce only one term in the
denominatordenominator
when it is simplified.Part 2
StartFraction sine 2 x Over 1 minus cosine 2 x EndFractionsin2x1−cos2x
|
equals=
|
StartFraction nothing Over 1 minus left parenthesis nothing right parenthesis EndFractionenter your response here1−enter your response here
|
|
|
equals=
|
StartFraction nothing Over nothing EndFractionenter your response hereenter your response here
|
Simplify the
denominatordenominator.
Enter the
numeratornumerator
found in the previous step. |
Part 3
The expression from the previous step then simplifies to
cotangent xcot x
using what?Reciprocal Identity
Even-Odd Identity
Pythagorean Identity
Quotient Identity
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