This is one question but I couldn't fit the whole question in one photo so I attached two photos, thank you :) Verify Property 2 of the definition of a probability density function over the given interval.f(x) =[-3,3]486What is Property 2 of the definition of a probability density function?O A. The area under the graph of f over the interval [a,b] is 1.O B. The area under the graph of f over the interval [a,b] is a.O C. The area under the graph of f over the interval [a,b] is b.Identify the formula for calculating the area under the graph of the function y = f(x) over the interval [a,b]. Choose the correct answer below.O A. bO B. a[rox) dx = [F(x); = F(b)-F(a)F(x) dx = [F(x)1; = F(a) – F(b)%3DaОС. аO D. bf(x) dx = [F(x)], = F(b) – F(a)f(x) dx = [F(x)l% = F(a) - F(b)baSubstitute a, b, and f(x) into the left side of the formula from the previous step.5x* dx486area = Next, determine F(x). First, find the antiderivative of f..4X dx =486Let C= 0 in the expression obtained above and let the resulting expression be F(x). Evaluate the result over [-3,3] using the far right side of the formula for the area.O-Darea =Simplify%3DIs Property 2 of the definition of a probability density function over the given interval now verified? Choose the correct answer below.O A. Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals 1.O B. Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals b.O C. Property 2 of the definition of a probability density function over the given interval has not been verified because the expression in the previous step does not equal the expected area valuO D. Property 2 of the definition of a probability density function over the given interval has been verified since the expression in the previous step equals a.

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Verify Property 2 of the definition of a probability density function over the given interval. f(x) = x*, [-3,3] %3D