Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 3Fe2O3(s) + H₂(g) →2Fe3O4(s) + H₂O(g) AH (Fe2O3 (8)) = -824.2 kJ/mol AH (H₂ (9)) = 0.0 kJ/mol AH (Fe3O4(s))=-1118.4 kJ/mol AH (H₂O(g)) = -241.8 kJ/mol AH TXT kJ

Chemistry by OpenStax (2015-05-04)
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Chapter5: Thermochemistry
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Problem 69E: Using the data in Appendix G, calculate the standard enthalpy change for each of the following...
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Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
3Fe2O3 (s) + H₂(g) → 2Fe3O4(s) + H₂O(g)
AH (Fe₂O3(s)) = -824.2 kJ/mol
AH (H₂(g)) = 0.0 kJ/mol
AH (Fe3O4(s)) = -1118.4 kJ/mol
AH (H₂O(g)) = -241.8 kJ/mol
ΔΗ° =
TXT
kJ
Transcribed Image Text:Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 3Fe2O3 (s) + H₂(g) → 2Fe3O4(s) + H₂O(g) AH (Fe₂O3(s)) = -824.2 kJ/mol AH (H₂(g)) = 0.0 kJ/mol AH (Fe3O4(s)) = -1118.4 kJ/mol AH (H₂O(g)) = -241.8 kJ/mol ΔΗ° = TXT kJ
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