Use the References to access important values if needed for this question. The concentration of H3ASO3 in a solution is determined by titration with a 0.1945 M Ce** solution. The balanced net ionic equation for the reaction is: 2Ce**(aq) + H3ASO3(aq) + 5H,O(1) 2Ce*(aq) + H3ASO,(aq) + 2H3O*(aq) (a) If 19.83 mL of the 0.1945 M Ce** solution are needed to react completely with 30.00 mL of the H3ASO, solution, what is the concentration of the H3ASO3 solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Cet ion is transferred to a volumetric flask and diluted to 300. mL. What is the concentration of Cein the diluted solution? Submit Answer 5 question attempts remaining
Use the References to access important values if needed for this question. The concentration of H3ASO3 in a solution is determined by titration with a 0.1945 M Ce** solution. The balanced net ionic equation for the reaction is: 2Ce**(aq) + H3ASO3(aq) + 5H,O(1) 2Ce*(aq) + H3ASO,(aq) + 2H3O*(aq) (a) If 19.83 mL of the 0.1945 M Ce** solution are needed to react completely with 30.00 mL of the H3ASO, solution, what is the concentration of the H3ASO3 solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Cet ion is transferred to a volumetric flask and diluted to 300. mL. What is the concentration of Cein the diluted solution? Submit Answer 5 question attempts remaining
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter16: Solutions
Section: Chapter Questions
Problem 100E: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a...
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This titration is an example of a redox titration because oxidation states of species are changing. Titrant Ce4+ is a oxidising agent and it oxidise As3+ to As5+ oxidation state i.e. Change in oxidation state of 2 so n-factor for arsenic acid is 2. While Ce4+ goes to Ce3+ i.e. change in oxidation state of 1, so n-factor for cerium is 1.
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