uppose Louise wants to breed parakeets that are yellow wit rere yellow with patterned feathers, she found that there we rovided, determine the number of genes and alleles that con Phenotype Number patterned yellow wings 27 solid yellow wings 9 patterned white wings 9 solid white wings 3.
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- In certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?Suppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, It, and Le. The gene si is associated with the silky fur phenotype, and It is associated with the long-tailed phenotype. Both si and It are recessive mutations with respect to wild type. Le is a dominant mutation that confers the lethargic phenotype. The geneticist first crosses true-breeding lethargic rabbits to true-breeding silky fur, long-tailed rabbits. Next, the geneticist backcrosses the Fj progeny to the silky fur, long-tailed parents, and obtains the results reported in the table. Phenotype Number lethargic 815 silky fur, long-tailed 807 long-tailed 177 silky fur, lethargic 179 silky fur 7 long-tailed, lethargic 5 silky fur, long-tailed, lethargic 29 wild type 29 Place the genes in the correct order in the chromosome. Answer Bank si It LeIn a species of plant, two genes control flower color. The red allele(R) is dominant to the white allele (r); the color-producing allele(C) is dominant to the non-color-producing allele (c). You suspectthat either an rr homozygote or a cc homozygote will producewhite flowers. In other words, rr is epistatic to C, and cc is epistatic to R. To test your hypothesis, you allow heterozygous plants(RrCc) to self-fertilize and count the offspring. You obtain the following data: 201 plants with red flowers and 144 with white flowers. Conduct a chi square analysis to see if your observed data areconsistent with your hypothesis.
- Suppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, sf, and H. The gene si is associated with the silky fur phenotype, and sf is associated with the short-footed phenotype. Both si and sf are recessive mutations with respect to wild type. H is a dominant mutation that confers the hyper phenotype. The geneticist first crosses true-breeding hyper rabbits to true-breeding silky fur, short-footed rabbits. Next, the geneticist backcrosses the F₁ progeny to the silky fur, short-footed parents, and obtains the results reported in the table. Phenotype hyper silky fur, short-footed short-footed silky fur, hyper silky fur short-footed, hyper silky fur, short-footed, hyper wild type Place the genes in the correct order in the chromosome. LLIIN HEL H Number 815 807 175 169 4 5 27 29 Answer Bank si sfScurs in cattle is a sex-influenced trait. A cow with no scurs whosemother had scurs had offspring with a bull with scurs whose fatherhad no scurs. What are the probabilities of each of the followingcombinations of offspring? A. The first offspring will not have scurs.B. The first offspring will be a male with no scurs.C. The first three offspring will be females with no scurs. In 1919, Calvin Bridges began studying an X-linkedrecessive mutation causing eosin-colored eyes inDrosophila. Within an otherwise true-breedingculture of eosin-eyed flies, he noticed rare variantsthat had much lighter cream-colored eyes. By intercrossing these variants, he was able to make a truebreeding cream-eyed stock. Bridges now crossedmales from this cream-eyed stock with true-breedingwild-type females. All the F1 progeny had red (wildtype) eyes. When F1 flies were intercrossed, the F2progeny were 104 females with red eyes, 52 maleswith red eyes, 44 males with eosin eyes, and14 males with cream eyes. Assume that thesenumbers represent an 8:4:3:1 ratio.a. Formulate a hypothesis to explain the F1 and F2results, assigning phenotypes to all possiblegenotypes.b. What do you predict in the F1 and F2 generations if the parental cross is between truebreeding eosin-eyed males and true-breedingcream-eyed females?c. What do you predict in the F1 and F2 generationsif the parental cross is…
- A mouse from a true-breeding population with normal gait was crossed to a mouse displaying an oddgait called dancing. The F1 animals all showednormal gait.a. If dancing is caused by homozygosity for the recessive allele of a single gene, what proportion ofthe F2 mice should be dancers?b. If mice must be homozygous for recessive allelesof each of two different genes to have the dancing phenotype, what proportion of the F2 shouldbe dancers if the two genes are unlinked?(Assume that all the mice in the populationwith normal gait were homozygous fordominant alleles.)c. When the F2 mice were obtained, 42 normal and8 dancers were seen. Use the chi-square test todetermine if these results better fit the one-genemodel from part (a) or the two-gene model frompart (b).In 1981, a stray black catwith unusual rounded,curled-back ears was adoptedby a family in California.Hundreds of descendants ofthe cat have since been born,and cat fanciers hope to develop the curl cat into a showbreed. Suppose you ownedthe first curl cat and wantedto develop a true-breeding variety. How would you determinewhether the curl allele is dominant or recessive? How wouldyou obtain true-breeding curl cats? How could you be sure theyare true-breeding?In corn plants, a dominant allele (1) inhibits the expression of kernel color, while the recessive allele (1) promotes the expression of kernel color when homozygous. Another dominant allele, (P), causes purple kernel color, while the homozygous recessive genotype (pp) causes red kernels. Assuming that these alleles assort independently, predict the phenotypic ratio of the offspring if two plants dihybrid for these characteristics are crossed.
- With regard to heterosis, is each of the following statements consistent with the dominance hypothesis, the overdominance hypothesis, or both? A. Strains that have been highly inbred have become monomorphicfor one or more recessive alleles that are somewhat detrimentalto the organism. B. Hybrid vigor occurs because highly inbred strains are monomorphicfor many genes, whereas hybrids are more likely to beheterozygous for those same genes.C. If a gene exists in two alleles, hybrids are more vigorousbecause heterozygosity for the gene is more beneficial thanhomozygosity of either allele.In a drosophila , the allele for normal wing length is dominant over the allele for short wings. In a population of 1000 individuals, 360 show the recessive phenotype. How many individuals would you expect to be homozygous dominant for the trait.In a species of plant, two genes control flower color. The redallele (R) is dominant to the white allele (r); the color-producingallele (C) is dominant to the non-color-producing allele (c). Yoususpect that either an rr homozygote or a cc homozygote willproduce white flowers. In other words, rr is epistatic to C, andcc is epistatic to R. To test your hypothesis, you allowed heterozygousplants (RrCc) to self-fertilize and counted the phenotypesof the offspring. You obtained the following data: 201 plantswith red flowers and 144 with white flowers. Conduct a chisquare test to see if your observed data are consistent with yourhypothesis.