TRial 1 Trial 2 Trial 3 0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH Final reading (ml) of the buret 20.00 19.90 40.00 39.70 20.00 45.30 Initial reading (ml) of the buret 0.00 0.00 20.00 19.90 0.00 25.50 Volume Used (ml) for the trial Compute for 1.00 ml HCl in terms of ml. NaOH for EACH Trial. Compute for 1.00 ml NaOH in terms of ml. HCl for EACH Trial.
TRial 1 Trial 2 Trial 3 0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH Final reading (ml) of the buret 20.00 19.90 40.00 39.70 20.00 45.30 Initial reading (ml) of the buret 0.00 0.00 20.00 19.90 0.00 25.50 Volume Used (ml) for the trial Compute for 1.00 ml HCl in terms of ml. NaOH for EACH Trial. Compute for 1.00 ml NaOH in terms of ml. HCl for EACH Trial.
Chapter15: Complex Acid/base Systems
Section: Chapter Questions
Problem 15.27QAP
Related questions
Question
|
TRial 1 |
Trial 2 |
Trial 3 | ||||
|
0.1 N HCl |
0.1 N NaOH |
0.1 N HCl |
0.1 N NaOH |
0.1 N HCl |
0.1 N NaOH |
|
|
Final reading (ml) of the buret |
20.00 |
19.90 |
40.00 |
39.70 |
20.00 |
45.30 |
|
Initial reading (ml) of the buret |
0.00 |
0.00 |
20.00 |
19.90 |
0.00 |
25.50 |
|
Volume Used (ml) for the trial |
- Compute for 1.00 ml HCl in terms of ml. NaOH for EACH Trial.
- Compute for 1.00 ml NaOH in terms of ml. HCl for EACH Trial.
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