Trans-oleic acid (18:1,D9) has a melting temperature of (44.5C) and cis-oleic acid (18:1,D9) has a melting point of (13.4C). Briefly explain the difference in melting points between the two. tw.
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- Trans-oleic acid (18:1,D9) has a melting temperature of (44.5C) and cis-oleic acid (18:1,D9) has a melting point of (13.4C). Briefly explain the difference in melting points between the two.A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 70 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont.) Ni(OH), Zn(OH), Cu(OH), Hg(OH)2 Sn(OH), Cr(OH), Al(OH), Fe(OH), Co(OH), Sulfides Baf, MGF2 PbF, SrF, CaF, 2.4 x 10-6 1.9 x 10-12 1.6 x 10-16 8 x 10-8 X 10-8 7.9 x 10-10 3.9 x 10-11 2 x 10-16 4.5 X 10-17 4 1.6 x 10-19 X 10-26 X 10-27 6.7 x 10-31 Carbonates NiCO, CaCO, BaCO, SrCO, CuCO, ZnCO, MNCO, FeCo, Ag,CO, CdCo, PbCO, M9CO, Hg,CO, 1.4 X 10-7 4.7 x 10-9 3. Chlorides 1.6 x 10-9 PbCl, AgCI Hg,Cl, х 10-33 X 10-38 2.5 x 10-43 1.6 x 10-5 X 10-10 2.5 x 10-10 2 x 10-1o 8.8 x 10-11 2.1 X 10-11 7 1.7 x 10-10 1.1 X 10-18 6. Bromides PbBr2 X 10-16 X 10-19 X 10-21 5 x 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 4.6 x 10-6 5.0 x 10-13 Fes 4. AgBr Hg,Br, 8.2 x 10-12 NiS Cos Zns 1.3 x 10-22 3 5.2 x 10-12 1.5 x 10-15 1 x 10-15 9.0 x 10-15…A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 88 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont) Ni(OH), Zn(OH), Cu(OH), Hg(OH), Sn(OH), Cr(OH), A(OH), BaF, MgF, PbF, SrF, CaF, 2.4 x 10-5 X 10-8 x 10-8 1.9 x 10-12 1.6 x 10-16 4.5 X 10-17 1.6 x 10-19 3 2 x 10-16 4 Carbonates 7.9 x 10-10 3.9 x 10-11 X 10-26 NiCO, CaCO, BaCo, SrCO, CuCO, ZnCO, MnCO, 1.4 x 10-7 3 10-27 4.7 x 10- 6.7 x 5 x 6 x 10-38 2.5 x 10-43 Chlorides 10-31 1.6 x 10- 1.7 x 10-10 1.1 x 10-18 1.6 x 10-9 7 x 10-10 2.5 x 10-10 10-33 PBCI, AgCi Hg,Cl, Fe(OH), Co(OH), Sulfides 2 x 10-10 8.8 x 10-11 2.1 x 10-11 Bromides X 10-16 X 10-19 3 x 10-21 X 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 7. PbBr, AgBr Hg, Br, 4.6 x 10-6 5.0 x 10-13 Feco Ag,CO, CdCo, PBCO, MgCO, Hg,CO, Fes 4 8.2 x 10-12 5.2 x 10-12 1.5 x 10-15 1 x 10-15 NiS 1.3 x 10-22 Cos ZnS lodides Pbl, Agl…
- Quinine ( C20 H24 N2 O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine, pK, = 5.1 and pK, = 9.7 ( pKp = – log Kp). Only 1 g quinine will dissolve in 1920.0 mL of solution. Calculate the pH of a saturated aqueous solution of quinine. Consider only the reaction | Q+ H2O= QH+ + OH- described by pK, where Q = quinine. pH =A 10.00-mL aliquot of unknown oxalic acid solution required 15.44 mL of 0.011 17 M KMnO4 solution to reach the purple end point. A blank titration of 10 mL of similar solution containing no oxalic acid required 0.04 mL to exhibit detectable color. Find the concentration of oxalic acid in the unknown.