To which value would the following expression reduce if the universe of discourse is the set of positive integers between 1 and 12 (inclusive), and if the contents of sets A, B, C, and D were {2, 4, 5, 8, 9, 11, 12}, {3, 4, 5, 6, 7, 8, 11, 12)}, {2, 4, 5, 6, 7, 8, 10, 11, 12}, and {1, 3, 4, 5, 7, 8, 9, 11, 12)}, respectively? (((D\C) \ ((BU (A)))) Select one: O (4, 5, 6, 7, 8, 9, 11, 12} O {1, 2, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {2, 4, 5, 7, 8, 9, 10, 11} O {2, 4, 5, 6, 7, 9, 10, 11, 12} O (2, 4, 5, 6, 7, 8, 9} O {2, 4, 5, 6, 8, 9, 10, 11, 12} O none of these options O {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {2, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {5, 6, 7, 9, 10, 11, 12}

To which value would the following expression reduce if the universe of discourse is the set of positive integers between 1 and 12 (inclusive), and if the contents of sets A, B, C, and D were {2, 4, 5, 8, 9, 11, 12}, {3, 4, 5, 6, 7, 8, 11, 12)}, {2, 4, 5, 6, 7, 8, 10, 11, 12}, and {1, 3, 4, 5, 7, 8, 9, 11, 12)}, respectively? (((D\C) \ ((BU (A)))) Select one: O (4, 5, 6, 7, 8, 9, 11, 12} O {1, 2, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {2, 4, 5, 7, 8, 9, 10, 11} O {2, 4, 5, 6, 7, 9, 10, 11, 12} O (2, 4, 5, 6, 7, 8, 9} O {2, 4, 5, 6, 8, 9, 10, 11, 12} O none of these options O {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {2, 4, 5, 6, 7, 8, 9, 10, 11, 12} O {5, 6, 7, 9, 10, 11, 12}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Consider the following four sets where the domain is the set of positive integers. A = { x | x is a positive integer less than 10} B= {x|x is a prime number less than 10} C= {x|x is an even number less than 10} D= {x|x is a power of 2} Answer the following questions (1) What is AU B|? (2) What is P(A N C)? (3) What is | P((AU C)- (CU D))|?
For (∃ x)(P(x,b)) Would an example of this being true if the domain was all the Avengers and x was green skin, then "b" being the Hulk would make this true. Am example of this being false would be: If the domain was all integers and x was positive, even integers and "b" was integers greater than zero.
Let A = {4, 5, 11, 16}, B = {6, 8, 11, 12, 13, 16}, C = {2, 3, 5, 7, 11},D = {8, 12, 16}, E = {6, 11, {12, 13}, 16}, F = {n ∈ Z | 1 ≤ n ≤ 12, and n is prime}. (Note: you can take multiple questions from my cycle if u want)
Choose the correct phrase * 1.1 • The Domain of f(x) = V1 – x is 1. [-1,0) 2. (-0, 1] 3. (-∞, 1) 4. [1, 0) 1 O 2 O 3 4 O
Correct answer will be upvoted else downvoted. Computer science. You are given three positive (more prominent than nothing) integers c, d and x. You need to track down the number of sets of positive integers (a,b) with the end goal that balance c⋅lcm(a,b)−d⋅gcd(a,b)=x holds. Where lcm(a,b) is the most un-normal various of an and b and gcd(a,b) is the best normal divisor of an and b. Input The primary line contains one integer t (1≤t≤104) — the number of experiments. Each experiment comprises of one line containing three integer c, d and x (1≤c,d,x≤107). Output For each experiment, print one integer — the number of sets (a,b) to such an extent that the above uniformity holds.
Let A = {a, b, c}, B = {x, y}, and C = {0, 1}. Identify B × B × B.
If p=T, q=unknown and r=F, what is p ∨ r ∧ q?
Given two strings X and Y, where X consists of the sequence of symbols X1, X2, Xm and Y consists of the sequence of symbols y₁,Y2, ***,yn. Consider the sets {1, 2, ..., m} and {1, 2, ..., n} as representing the different positions in the strings X and Y, and consider a matching of these sets, where a matching is a set of ordered pairs with the property that each item occurs in at most one pair. A matching M of these two sets is an alignment if there are no "crossing" pairs: if (i,j). (i*,j') = Mandi 0 that defines a gap penalty. For each position of X or Y that is not matched in M (it is a gap), we incur a cost of 8. Second, for each pair of letters p and q (p + q) in our alphabet, there is a mismatch cost of app for lining up p with q. Thus, for each (i,j) = M, we pay the appropriate mismatch cost axiy for lining up x; with y;. The cost of M is the sum of its gap and mismatch costs, and the problem seeks an alignment of minimum cost. Define the minimum alignment cost OPT(i,j) (0 ≤ i ≤…
TM M = (Q, E, I, 6, 90, 9a, qr), where Q = {90, 91, 92, 9a, 9r}, Σ = {0, 1}, r = {0, 1, L}, and 8 is: 8(qo, U) = (qr, U, R) 8(90, 0) = 8(go, 1) (91, 0, R) (qo, 1, R) = 8(g1, L) = (ga, U, R) 8(91,0) = (91, 0, R) 8(91, 1) = (92, 1, R) = (92, U, R) 8(92, U) 8(92, 0) = (90, 0, R) 8(92, 1) = (92, 1, R) i. Prove that M is NOT a decider. ii. Mathematically describe the language A that M recognises. Prove that A ≤ L(M). iii. Prove A = L(M). iv. Is A Turing-decidable? [Give clear reasons for your answer. No need for a formal proof.]
Order the following sentences so that they form a direct proof of the statement: If x and y are rational numbers, then 3x + 2y is also a rational number. Choose from this list of sentences Since b, d are integers, bd is an integer. By the definition of rational numbers, x = a/b where a and b are integers and b# 0, and y = c/d where c and d are integers and d 0. Since 3x + 2y can be expressed as a ratio of two integers where the denominator is not zero, 3x + 2y is a rational number. Since a, b, c, d are integers, 3ad + 2bc is an integer. Let x and y be rational numbers. Since b 0 and d # 0, bd # 0. It follows that 3x + 2y = 3a/b + 2c/d = (3ad + 2bc)/(bd) Direct proof of the statement (in order):
Convert the following NFA into a DFA. M=(Q, E, 8, 9o, F) Q={A, B, C, D} Σ= {a,b,c} 8(A, a) = {A, B} 8(B, a) = {B} 8(B, c) = {D} 8(C, a) = {A} 8(C,b) = {C} 8(D, c) = {B,C} 90 = A F = {C}
Help me