Three titration trials were performed and three molar concentrations of NaOH were calculated. The three molar concentrations are as follows: 0.10 M 0.12 M 0.19 M Calculate the standard deviation of the molar concentration of NaOH.
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- Titration volume measurements Trial 1 Trial 2 Trial 3 Inital volume NaOH (mL) 50.00 50.00 50.00 Final volume NaOH (mL) 14.68 8.91 10.00 Volume NaOH used (mL)A 10.00-mL aliquot of an HCI solution of known concentration (3.800 g/L) was titrated against a 4.100 g/L NaOH solution. Calculate the % error given the titration results below: Initial Volume (ml) Final Volume (ml) Type your answer... Blank 42.35 42.70 Trial 1 1.45 11.62 Trial 2 24.87 35.85 Trial 3 18.80 28.01LabQuest 17 DATA TABLE Trial 1 2 3 4 5 6 Concentration (mol/L) 0.080 0.16 0.24 0.32 0.40 Unknown number Absorbance (no units) 0.2711 0.437 1.480 1.932 2.171 0.3 DATA ANALYSIS 1. Describe an alternate method for determining the molar concentration of your unknown sample of copper (II) sulfate solution, using the standard data.
- Data Table Test mL of mL of pH tube HOAc NaOAc Trial Trial pH HOAC pH Average Millimoles Millimoles pKa NaOAc 1 2 1 1.00 9.00 5.0 5.0 2 3.00 7.00 6.0 6.0 3 5.00 5.00 5.0 5.0 4 7.00 3.00 5.0 6.0 5 9.00 1.00 5.0 6.0 Average calculated pKa Actual pKa from textbookSheet 5 From the following data determine the following: Define outlier and then identify the outlier in the data. Determine if the outlier should be kept of discarded from the data. Trial 1 2 3 4 HCl (mL) 22.3 28.4 29.8 29.3 NaOH (mL) 35.2 35.1 34.9 35.0search Remaining Time: 1 hour, 42 minutes, 08 seconds. * Question Completion Status: Moving to the next question prevents changes to this answer. Question 6 a noition Save Answer Consider the titration (titration of 10 ml lemon juice (citric acid) with 0.10 M NaOH) results obtained for four trials and the original juice has been diluted ten-fold (1+9 dilution) to obtain the diluted juice: Burette readings Trial Final ml Initial ml O E Moving to the next question prevents changes to this answer. 1 The amount (Molarity) of citric acid present in lemon juice will be: NB. Write the only value with 8.5 0 2 17.7 8.5 3 24.6 17.7 55255 4 31.3 24.6 (2) 4 Question 6 of 27 > 33°C Question 6 of 27 ▲) ENG 14:04 05/10/2022
- C030 BY NC SA S. Alvanipour, Y, Gedeon, G. Zoorob, CC BY-NC-SA 4.0 B. Determination of unknown acid concentration Unknown Acid number Volume of acid used (ml) Initial buret reading (mL) Final buret reading (ml) Volume of NaOH used (ml) Molarity of NaOH Trial 1 Unknown Quid 25.0ml Ome 12.4ml 12.4ml -10m Calculated molarity of HCI (M) Show a sample calculation of HCI molarity AVERAGE MOLARITY OF Unknown HCI Show a sample calculation of NaOH molarity: Trial 2 Unknown 25-am omo 12.5ml 12.5ml -lom Trial 3 Unknown af 20% ome come 12.630 12.6ml -tomTable 1: Volumes in of iodine in mL used to titrate mixtures of 10 mL of reaction mix and 10 mL of urine. student trial 1 trial 2 trial 3 total volume (mL) a 12.6 11.8 12.5 300 290 b. 10.6 10.7 10.6 11.1 118 12. 10.9 405 13.0 12.5 349 mg vit. C mL iodine TV (mL/hour) 10 mL urine aliquot TVC (mg/hour) =7 (mL) · CF !! What is the hourly vitamin C excretion rate (mg/h) of student b if the CF is 1.06? (include no more than two decimals in your answer, e.g.: 123.45, and do not type the units) 10.6 need ASAPpls answer 16,17,18
- When we make a calibration curve, we want the range of calibration standards to the analyte concentrations in the samples. If this is not the case, we will have to the samples, depending on the analyte concentration. O Exclude, concentrate or dilute O Include, spike O Include, concentrate or dilute None of These O Exclude, calculate the concentration of You have prepared a set of calibration standards for nitrate in surface water where you are using Beer's Law to generate the calibration curve. The calibration equation for the standards you have prepared between 1 and 15 ppm is y = 0.0820x +0.00900. You analyze a 3.00 mL water sample and generate an absorbance response of 1.12. You report the concentration of nitrate in this sample as: O None of These O 4.52 ppm O The concentration is out of range so it cannot be reported O 13.5 ppm O 13.5 absorbancesing the pictures please help me with these questions.-Volume of unknown acid___-Average molarity of NaOH from above__-mL of NaOH at equivalence point__-molarity of unknown acid__(there was only one trial so average molarity and standard deviation are not required)Data and Observations Section Date volume of HCI solution used, mL concentration of NaOH solution, M initial volume of NaOH solution, mL determination 1 25 ml determination 2 25 mL 0.0500 M 0.0500 M 0mL Oml equivalence-point volume of NaOH solution, mL 30.5mL 2.3ml Calculations and Conclusions Show your calculations in the space provided. Include units on all quantities and round results to the correct number of significant figures. 1. Determine the volume of NaOH solution required to titrate the HCI solution to the equivalence point. determination 1 determination 2 2. Calculate the original concentration of the HCI solution (M). determination 1 determination 2 3. Calculate the average concentration of the HCI solution (M). average HCl concentration, M