The voltage, V, in a simple electrical circuit is slowly decreasing as thebattery wears out. The resistance, R, is slowly increasing as the resistorheats up. Use Ohm's Law, V = IR, to find the rate at which thecurrent, I, is dropping at the moment when R = 100 N, I = 0.12 A.%3DAPdt= -0.002 , anddR= 0.025 2.dtNote: voltage is measured in volts (V), resistance is measured in ohms (2), and current is measured in amperes (A); 1 V = (1 A) · (1 N).

Ohm's law gives, V=IR Taking the derivative with respect to time on both sides of the above…

The voltage, V, in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance, R. is slowly increasing as the resistor heats up. Use Ohm's Law, V == IR to find the rate at which the %3D current, I, is dropping at the moment when R = 100 N. I = 0.12 A. dR AP = = 0.025 !. dt -0.002 , and %3D dt

The voltage, V, in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance, R. is slowly increasing as the resistor heats up. Use Ohm's Law, V == IR to find the rate at which the %3D current, I, is dropping at the moment when R = 100 N. I = 0.12 A. dR AP = = 0.025 !. dt -0.002 , and %3D dt

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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