The standard enthalpy change for the following reaction is 433 kJ at 298 K. KClO4(s)---->  K(s) + 1/2 Cl2(g) + 2 O2(g)        ΔH° = 433kJ What is the standard enthalpy change for this reaction at 298 K? K(s) + 1/2 Cl2(g) + 2 O2(g)--->  KClO4(s)

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Chapter5: Thermochemistry
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The standard enthalpy change for the following reaction is 433 kJ at 298 K.

KClO4(s)---->  K(s) + 1/2 Cl2(g) + 2 O2(g)

             ΔH° = 433kJ

What is the standard enthalpy change for this reaction at 298 K?

K(s) + 1/2 Cl2(g) + 2 O2(g)--->  KClO4(s)

 

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