The point x = 0 is a regular singular point of the given differential equation. 2xy" + 7y' + xy = 0

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 59E: According to the solution in Exercise 58 of the differential equation for Newtons law of cooling,...
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16** +.
The point x =
O is a regular singular point of the given differential equation.
2xy" + 7y' + ху %3D 0
+ r
Substitute y =
C
into the differential equation and collect terms to rewrite as a single power series.
n=0
00
2ху" + 7y' + ху %3
1
+
k +r - 1
k=2
Show that the indicial rootsr of the singularity do not differ by an integer. (List the indicial roots below as a comma-separated list.)
r =
Use the method of Frobenius to obtain two linearly independent series solutions about x = 0. Form the general solution on (0, 0).
1
2
- X
-) + c<(1-
1
1
y = Cqx-5/2(1
x²
24
+
+
+
2112
-
16
1152
**..) + c_(1 -
.) + c2(1 - 1
.) + c<(1 + ?
1 2
1
1
y = C,x=5/2(1 +
1
+
936
4
+
4
24
18
Oy = C;x-5/2(1
1x? +
1
+
x²
+
18
936
1152
1
1
1. 2
1
y = C;x=5/2(1
2
+
4
+
%3D
-
18
936
2
24
:)
1
1
y = C,x-5/2(1
,2
+
+ C,
x²
16
1
x4 + . . .
+
1
+
1152
24
2112
)
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Transcribed Image Text:16** +. The point x = O is a regular singular point of the given differential equation. 2xy" + 7y' + ху %3D 0 + r Substitute y = C into the differential equation and collect terms to rewrite as a single power series. n=0 00 2ху" + 7y' + ху %3 1 + k +r - 1 k=2 Show that the indicial rootsr of the singularity do not differ by an integer. (List the indicial roots below as a comma-separated list.) r = Use the method of Frobenius to obtain two linearly independent series solutions about x = 0. Form the general solution on (0, 0). 1 2 - X -) + c<(1- 1 1 y = Cqx-5/2(1 x² 24 + + + 2112 - 16 1152 **..) + c_(1 - .) + c2(1 - 1 .) + c<(1 + ? 1 2 1 1 y = C,x=5/2(1 + 1 + 936 4 + 4 24 18 Oy = C;x-5/2(1 1x? + 1 + x² + 18 936 1152 1 1 1. 2 1 y = C;x=5/2(1 2 + 4 + %3D - 18 936 2 24 :) 1 1 y = C,x-5/2(1 ,2 + + C, x² 16 1 x4 + . . . + 1 + 1152 24 2112 ) Need Help? Read It Watch It
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