The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t2, where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t2, where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter1: Introduction: The Nature Of Science And Physics

Section: Chapter Questions

Problem 10PE: (a) Refer to Table 1.3 to determine the average distance between the Earth and the Sun. Then...

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Question

The height of a projectile fired straight up in the air with an initial velocity of 64 ft/s is h = 64t - 16t², where h is height in feet and t is time in seconds. The table represents the data for another projectile. Which projectile goes higher? How much higher?

Table Data

Time (t)	Height (h)
0.5	20
1	32
1.5	36
2	32

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