The first five vibrational energy levels of ¹H¹²71 are at 1144.83, 3374.90, 5525.51, 7596.66, and 9588.35 cm¹. Treating the molecule as an anharmonic oscillator, estimate the dissociation energy of the molecule in units of reciprocal centimetres (cm-¹). [Note: m(¹H) = 1.0078 u, m(¹271) = 126.9045 u; assume the second order anharmonicity constant, Ye, to be zero.]

Physical Chemistry
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Author:Ball, David W. (david Warren), BAER, Tomas
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Chapter14: Rotational And Vibrational Spectroscopy
Section: Chapter Questions
Problem 14.61E
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The first five vibrational energy levels of ¹H¹27 I are at 1144.83, 3374.90, 5525.51, 7596.66,
and 9588.35 cm¹. Treating the molecule as an anharmonic oscillator, estimate the
dissociation energy of the molecule in units of reciprocal centimetres (cm-¹).
[Note: m(¹H) = 1.0078 u, m(¹271) = 126.9045 u; assume the second order anharmonicity
constant, Ye, to be zero.]
[Note: Use graph paper in your answer.]
Transcribed Image Text:The first five vibrational energy levels of ¹H¹27 I are at 1144.83, 3374.90, 5525.51, 7596.66, and 9588.35 cm¹. Treating the molecule as an anharmonic oscillator, estimate the dissociation energy of the molecule in units of reciprocal centimetres (cm-¹). [Note: m(¹H) = 1.0078 u, m(¹271) = 126.9045 u; assume the second order anharmonicity constant, Ye, to be zero.] [Note: Use graph paper in your answer.]
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