The equilibrium constant, Ke, for the following reaction is 5.10 x 10 at 548 K. NH₂Cl(s) NH3(g) + HCl(g) If an equilibrium mixture of the three compounds in a 4.06 L container at 548 K contains 1.08 mol of NH₂Cl(s) and 0.368 mol of NH3, the number of moles of HCI present is mol, A student ran the following reaction in the laboratory at 696 K: 2HI(g) H₂(g) + 1₂ (9) When she introduced HI(g) at a pressure of 3.15 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of 1₂ (9) to be 0.333 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction.

Chemistry: The Molecular Science
5th Edition
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Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
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The equilibrium constant,
Ke, for the following reaction is
5.10 x 10-6 at 548 K.
NH₂Cl(s)
NH3(g) + HCl(g)
If an equilibrium mixture of the three compounds in a 4.06 L container at 548 K contains 1.08 mol of
NH₂Cl(s) and 0.368 mol of
NH3, the number of moles of
HCI present is
mol,
A student ran the following reaction in the laboratory at 696 K:
2HI(g) H₂(g) + 1₂ (9)
When she introduced HI(g) at a pressure of 3.15 atm into a 1.00 L evacuated container, she found the equilibrium
partial pressure of I₂ (9) to be 0.333 atm.
Calculate the equilibrium constant, Kp, she obtained for this reaction.
Kp
Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 5.10 x 10-6 at 548 K. NH₂Cl(s) NH3(g) + HCl(g) If an equilibrium mixture of the three compounds in a 4.06 L container at 548 K contains 1.08 mol of NH₂Cl(s) and 0.368 mol of NH3, the number of moles of HCI present is mol, A student ran the following reaction in the laboratory at 696 K: 2HI(g) H₂(g) + 1₂ (9) When she introduced HI(g) at a pressure of 3.15 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of I₂ (9) to be 0.333 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp
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