The beam is supported by a fixed support at point A. There are 2 distributed loads applied to the beam.Neglect the weight and thickness of the beam.Take the origin for all functions to be at A. , i.e. start at the left and go right. Must use positive signconvention for V and M.W1AW2d1Values for the figure are given in the following table. Note the figure may not be to scale.VariableValuedi3 mW16 (kN)/mW23 (kN)/ma. For the interval 0 < x < 3 m, determine the equation for the Shear Force as a function of x, V(x).b. For the interval 0 < x < 3 m, Use integrals to determine the equation for the Moment as a function ofX, M(x).o Enter the coefficient of the x term as a fraction and the rest as decimals. for example,x41.4xc. Determine the magnitude of the max shear on the beam,Vmaxd. Determine the magnitude of the max bending moment on the beam, Mnmax

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The beam is supported by a fixed support at point A. There are 2 distributed loads applied to the beam. Neglect the weight and thickness of the beam. Take the origin for all functions to be at A. , i.e. start at the left and go right. Must use positive sign convention for V and M. W1 A W2 d1 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value di 3 m W1 6 (kN)/m W2 3 (kN)/m

The beam is supported by a fixed support at point A. There are 2 distributed loads applied to the beam. Neglect the weight and thickness of the beam. Take the origin for all functions to be at A. , i.e. start at the left and go right. Must use positive sign convention for V and M. W1 A W2 d1 Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value di 3 m W1 6 (kN)/m W2 3 (kN)/m

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.7.14P: Solve the preceding problem for the following data: x=1120106,y=430106,xy=780106,and=45.

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