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The autoionization of water can be expressed with the following balanced chemical equation: 2H₂O (1) H3O+ (aq) + OH- (aq) Calculate the standard change in free energy for the above reaction at SATP in kJ/mol. Kw = 1.0 x 10-¹4. 0.73 73.17 79.87 0.67

The autoionization of water can be expressed with the following balanced chemical equation: 2H₂O (1) H3O+ (aq) + OH- (aq) Calculate the standard change in free energy for the above reaction at SATP in kJ/mol. Kw = 1.0 x 10-¹4. 0.73 73.17 79.87 0.67

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
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The autoionization of water can be expressed with the following balanced chemical equation: 2H₂O (1) H3O+ (aq) + OH- (aq) Calculate the standard change in free energy for the above reaction at SATP in kJ/mol. Kw = 1.0 x 10-14. 0.73 73.17 79.87 0.67
Transcribed Image Text:The autoionization of water can be expressed with the following balanced chemical equation: 2H₂O (1) H3O+ (aq) + OH- (aq) Calculate the standard change in free energy for the above reaction at SATP in kJ/mol. Kw = 1.0 x 10-14. 0.73 73.17 79.87 0.67
Expert Solution
Step 1

Given: 2H2O(l)⇔H3O+(aq) + OH-(aq)

Kw is given to be 1.0 x 10-14.

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