The authors of a paper studied a random sample of 343 Twitter users. For each Twitter user in the sample, the tweets sent during a particular time period were analyzed and the Twitter user was classified into one of the following categories based on the type of mest sually sent. Category IS OC RT ME O Description Information sharing Opinions and complaints Random thoughts Me now (what I am doing now) Other The accompanying table gives the observed counts for the five categories (approximate values read from a graph in the paper). Twitter Type IS oc RT ME 0 Observed count 51 60 62 71 Carry out a hypothesis test to determine if there is convincing evidence that the proportions of Twitter users falling into each of the five categories are not all the same. Use a significance level of 0.05. (Hint: See Example 12.2.) et P₁ P₂ P3 P4 and ps be the proportions of Twitter users falling into the five categories. State the appropriate null and alternative hypotheses. Ho: P₁ = P₂ = P3 = P4 = Ps = 0.2 H.: He is not true.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 10CYU
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The authors of a paper studied a random sample of 343 Twitter users. For each Twitter user in the sample, the tweets sent during a particular time period were analyzed and the Twitter user was classified into one of the following categories based on the type of messages they
usually sent.
Category
IS
OC
RT
ME
O
Description
Information sharing
Opinions and complaints
Random thoughts
Me now (what I am doing now)
Other
The accompanying table gives the observed counts for the five categories (approximate values read from a graph in the paper).
Twitter Type IS OC RT ΜΕ 0
Observed count 51 60 62 99 71
Carry out a hypothesis test to determine if there is convincing evidence that the proportions of Twitter users falling into each of the five categories are not all the same. Use a significance level of 0.05. (Hint: See Example 12.2.)
Let P₁ P2 P3 P4, and p5 be the proportions of Twitter users falling into the five categories.
State the appropriate null and alternative hypotheses.
Ho: P₁ = P₂ = P3 P4 P5 = 0.2
H₂: Ho is not true.
| Ho: P₁ = P₂ = P3 = P4 = P5 = 343
H: Ho is not true.
O Ho: P₁ = P₂ = P3 = P4 = P5 = 70
H₂: Ho is not true.
Ho: P₁ = P₂ = P3 = P4 = P5 = 0.05
H: Ho is not true.
| Ho: P₁ = P₂ = P3 = P4 = P5 = 0.5
H: H is not true.
Calculate the test statistic. (Round your answer to two decimal places.)
x² = 20.50
X
Use technology to calculate the P-value. (Round your answer to four decimal places.)
P-value = 0.0004
Transcribed Image Text:The authors of a paper studied a random sample of 343 Twitter users. For each Twitter user in the sample, the tweets sent during a particular time period were analyzed and the Twitter user was classified into one of the following categories based on the type of messages they usually sent. Category IS OC RT ME O Description Information sharing Opinions and complaints Random thoughts Me now (what I am doing now) Other The accompanying table gives the observed counts for the five categories (approximate values read from a graph in the paper). Twitter Type IS OC RT ΜΕ 0 Observed count 51 60 62 99 71 Carry out a hypothesis test to determine if there is convincing evidence that the proportions of Twitter users falling into each of the five categories are not all the same. Use a significance level of 0.05. (Hint: See Example 12.2.) Let P₁ P2 P3 P4, and p5 be the proportions of Twitter users falling into the five categories. State the appropriate null and alternative hypotheses. Ho: P₁ = P₂ = P3 P4 P5 = 0.2 H₂: Ho is not true. | Ho: P₁ = P₂ = P3 = P4 = P5 = 343 H: Ho is not true. O Ho: P₁ = P₂ = P3 = P4 = P5 = 70 H₂: Ho is not true. Ho: P₁ = P₂ = P3 = P4 = P5 = 0.05 H: Ho is not true. | Ho: P₁ = P₂ = P3 = P4 = P5 = 0.5 H: H is not true. Calculate the test statistic. (Round your answer to two decimal places.) x² = 20.50 X Use technology to calculate the P-value. (Round your answer to four decimal places.) P-value = 0.0004
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