t E = {0, 1}. TRUE or FALSE (with explanation): (01)* = 0*1*.
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- I need help with this problem. Please help me, because I do not understand. if 14 > 7: print("Greater than 14") x = 2 print(x * 7) else: print("Less than") print(7)sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)Interest on a credit card’s unpaid balance is calculated using the average daily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is: averageDailyBalance = (netBalance * d1 - payment * d2) / d1. The interest on the unpaid balance is: interest = averageDailyBalance * interestRate where interestRate is the interest rate per month. Write a program that accepts as input netBalance, payment, d1, d2, and interestRate. The program outputs the interest. Format your output to two decimal places. Analyze and design this program. Write the code, compile and run it. Upload your analysis and design document and your .cpp source code file here.
- Q3: Interplanetary Spaceflight Milan Tusk is the richest person in the universe. After devoting decades of his life to further our space exploration technologies, he’s finally ready to retire. Being a space enthusiast, the first thing he wants to do is visit n planets p1, p2, …, pn, in this order. He’s currently on planet p0. Milan knows that the distance between planets pi and pi + 1 (for 0 ≤ i < n) is d[i]light years. His spaceship uses 1 tonne of fossil fuels per light year. He starts with a full tank and can fill up his tank at any of the n planets (but he must not run out in between two planets). There’s a huge cost to set up the spaceship for refuelling. Due to financial constraints (he’s not THAT rich), he can fill up his tank at most ktimes. In order to save money and make his spaceship lighter, Milan is looking for the smallest possible fuel tank that enables him to complete his space travel and reach planet pn. What is the smallest tank capacity that enables him to do so?…Interest on a credit card’s unpaid balance is calculated using the averagedaily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is:averageDailyBalance = (netBalance * d1 – payment * d2) / d1If the interest rate per month is, say, 0.0152, then the interest on the unpaid balance is:interest = averageDailyBalance * 0.0152Write a program that accepts as input netBalance, payment, d1, d2, and interest rate per month. The program outputs the interest. Format your output to two decimal places.]: Write a piece of code that calculates the uncertainty SP from the error propagation rule for sums, SP = 2√√√(SL)² + (SW)² A few hints: Again, you're translating the above equation into code. • Your result should be stored in a variable uncertainty_P_errorprop • For the square root function, use np. sqrt() • For squares, use ** #YOUR CODE HERE raise Not ImplementedError() ]: ▼ # Print the uncertainty print ("uncertainty of circumference P from error propagation: 11 , uncertainty_P_errorprop)
- 1- Let A = [2: 0.5: 4],and B=B(2:4). What are the value of a ,and B?le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"Complete the function below that takes in three integers (a,b,c) and returns the number of integers between a and b (inclusive of the endpoints) that are divisible by c. Make sure it tests a and b for divisibility by c! In [ ]: defhow_many_divisible(a,b,c):counter=0# YOUR CODE HEREraiseNotImplementedError()returncounter In [ ]: assert how_many_divisible(10,20,5) == 3 assert how_many_divisible(30,77,7) == 7 PYTHON jYPYTER