Situation 2] A surveyor was tasked to cut off a required area by a line throi the process of determining some required quantities there was a need to e triangle BDP as shown. If the area of BDP is 630905.65 sqm, ii. The length of dividing line BP is? D Trial Line 1419.63 m 12°17' k79928'

Situation 2] A surveyor was tasked to cut off a required area by a line throi the process of determining some required quantities there was a need to e triangle BDP as shown. If the area of BDP is 630905.65 sqm, ii. The length of dividing line BP is? D Trial Line 1419.63 m 12°17' k79928'

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Situation 2] A surveyor was tasked to cut off a required area by a line through a given point. In the process of determining some required quantities there was a need to evaluate the resulting triangle BDP as shown. If the area of BDP is 630905.65 sqm, The length of line DP is? The length of dividing line BP is? The bearing of dividing line BP is? i. ii. iI. Trial Line 1419.63 m 12°17' 79928' B Dividing Line P
Complete the earth work calculation sheet here and plot the resulting mass diagram. Divide ccy by 0.9 to convert to bcy Station 0 + 00 1 + 00 2 +00 3 +00 4 + 00 4 + 50 5 +00 6 +00 6 +50 7 +00 8 +00 9 +00 10+ 00 End- End- area cut (sf) 0 0 0 136 206 256 179 123 98 51 0 0 0 area Volume fill of cut (sf) (bcy) 0 87 162 0 0 3 15 185 225 300 Volume Strip Strip Total Total Adj. of fill cut fill fill Sum (ccy) (bcy) (bcy) fill (ccy) (ccy) (bcy) (bcy) DORMCORES SOO 13 37 56 20 38 16 23 39 22 0 0 0 0 1 5 20 69 73 cut (bcy) Mass ordinate (bcy)
Given data of area with irregular boundary, complete the table and determine the area by trapezoidal method. (0,0) is station A. 21.0, 35.0 35.0, 26.0 NA 14.0, 15.0 28.0, 15.0 Station A B C D E F G H interval Area 7.0, 23.0 0.0, 0.0 0.0, 12.0 offset unit/s sq. units 42.0, 33.0 * Express all values up to 3 decimal places but if the value is zero just input 0. ** In writing the answer/s: - do not include the unit. 49.0, 27.0 56.0, 18.0 - if the value is positive, do not include the sign - if the value is negative, include the sign without space, ex: value: - 33.000, input: -33.000 $6.0, 0.0
A triangular lot of 30,000 sq. meter is to be divided into two equal parts such that the cutting line is from intersection between sides AB and CA to side BC. Below are the following data: Sides Bearing Distance AB N 15° E BC S 20° E CA N 55° W Determine the length of side AB O 114.975 m O 413.860 m O 252.662 m O 328.218 m O 200.377 m
>Example3/ The following offsets are taken from a chain line to an irregular boundary towards right side of the chain line. Chainage 0 25 Offset 'm' 3.6 5.0 Calculate the area using 1. Trapezoidal Method 2.Simpson's method 50 6.5 75 5.5 100 7.3 125 6.0 150 4.0
Given the close traverse data below, Calculate the larger area by dividing this parcel of land into two parts by a line between two points (D and A). Hint: Use balance/adjusted measurement before partition. On your solution please indicate the following: o DA Lat • DA Dep o DMD o Total DA o Area of the larger part Line Length (m) Bearing AB 137.086 N 39.926° E BC 27.74 IS 59.358° CD 181.873 IS 4.418° DE 42.711 IS 17.439° EA 81.336 N 13.363°
The tract of land ABCDEA is to be divided into two parts by a line from point D parallel to BC. Using the length and direction information of the tract sides listed below, a) draw a sketch of the land tract b) b)compute the information required to establish the partitioning line: Note: The X and Y coordinate of point A is 10,000 and 10,000 respectively Side AB BC CD DE EA Length (m) 660.27 584.18 365.42 321.53 694.37 Bearing N75° 04'W S35° 14'W S80 ° 33'E S47° 43'E N32° 51'E For the above tract, establish the partition line that passes through point D and divides the traverse into two equal parts.
1. A line AE is divided into segments for measurement with a tape. The results were AB = 134.10 m ± 0.040 m, BC = 320.63 m ± 0.055 m, CD =173.73 m ± 0.056 m, and DE = 160.85 m ± 0.050 m. Determine the length of the line and the probable error of the measured length. 2. The four approximately equal sides of a tract of land were measured and the measurements included the following errors: ±0.085 m, ±0.014 m, ±0.175 m, and ± 0.205 m, respectively Determine the probable error for the total length (or perimeter) of the tract.
A pieces of land plotted on a map having scale 1:3000 and its dimensions was 25cm x 17 cm what is the area on a ground in Dounm unit. 1. Convert 2.765476 rad to deg.min.sec, and to grads 2. A pieces of land 2500 m2 plotted on a map having scale 1:1000 what would be the area on a map. 3. Convert the following values a. I degree to rad and to grad b. 400 grad to rad c. x/2 to grad and to time 4. The distance between Duhok and Erbil on the map scale of 1:2000 000 was measured 12cm. Then measured on a second map without scale was 9 cm. what is the scale of the second map. .
Line MN, 251m long was paced five times by the surveyor and recorded as follows: Trial No. Distance 121 122 3 120 4 122 121 Another line OP was paced four times again with the following results: Trial No. Distance 1 321 312 311 4 312 Determine the actual length of line OP? 2. 5. 2. 3.
2. Complete the profile level notes shown below, perform the customary arithmetic check, provide a detailed sketch, and a detailed solution. STA BS HI FS IFS ELEV BM25 0+ 000 5.3650 254.1458 2.3225 2+ 000 1.3256 4+ 000 2.8945 6+ 000 1.9978 TP, 4.2544 5.4444 8+ 600 1.6452 10 + 200 6.5874 12 + 500 5.8942 14 + 900 5.6100 16 + 300 3.2542 18 + 700 2.6540 TP2 2.0021 6.5566 16 + 200 7.4845 18 + 850 4.5100 20 + 300 5.8900 22 + 070 3.2010 BM26 5.6412
4. In the accompanying sketch, determine the area included between the base line and the irregular boundary. I1.6 9.0 8.5 8.3 5.9 Trace of the 4.5 Irregular Boundary 4.8 5.5 2.0 3.9 4.22.2 B 12.5 3.0 6.0 6.0 5.1 4.6 Bose Line ABC 4.7 4.9 Note: All dimensions are in meters. 8.3 10.2