2.45 ppm as a singlet in the 'H NMR spectrum and at ô 39.7 ppm also as a singlet in the13C{'H} (not shown). Clearly explain these observations. (Note: the small differences inshown below). Meanwhile the corresponding signals of the non deuterated DMSO appear at ôa septet at 8 39.5 ppm while the 'H NMR spectrum shows a quintet signal at 8 2.50 ppm (bothThe 13C{H} NMR signal of a sample of commercial deuterated DMSO (sold as DMSO-de) shows4.chemical shift are due to isotopic shift, do not account for them).画画8至1H-NMR of DMSO-d613C-NMR of DMSO-d6Lau chown below. The

The splitting of signals in NMR is due to spin-spin coupling. It means that the splitting of an atom…

shown below). Meanwhile the corresponding signals of the non deuterated DMSO appear at 8 2.45 ppm as a singlet in the 'H NMR spectrum and at & 39.7 ppm also as a singlet in the The 13C{'H} NMR signal of a sample of commercial deuterated DMSO (sold as DMSO-ds) shows 13C{H} (not shown). Clearly explain these observations. (Note: the small differences in a septet at 8 39.5 ppm while the 'H NMR spectrum shows a quintet signal at 8 2.50 ppm (both chemical shift are due to isotopic shift, do not account for them).

shown below). Meanwhile the corresponding signals of the non deuterated DMSO appear at 8 2.45 ppm as a singlet in the 'H NMR spectrum and at & 39.7 ppm also as a singlet in the The 13C{'H} NMR signal of a sample of commercial deuterated DMSO (sold as DMSO-ds) shows 13C{H} (not shown). Clearly explain these observations. (Note: the small differences in a septet at 8 39.5 ppm while the 'H NMR spectrum shows a quintet signal at 8 2.50 ppm (both chemical shift are due to isotopic shift, do not account for them).

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL3: Carbon (13c) Nmr Spectroscopy

Section: Chapter Questions

Problem 11E

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